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Lina20 [59]
3 years ago
12

The area of a rectangle is X queered minus 2X -15 and the length of the rectangle is X +3 find the width of the rectangle The ar

ea of a rectangle is X queered minus 2X -15 and the length of the rectangle is X +3 find the width of the rectangle

Mathematics
1 answer:
Brums [2.3K]3 years ago
8 0
Hope this helps........

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12

Step-by-step explanation:

AD is 6. a bisector splits a line in half. X would equal 6 meaning AD would equal 12.

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Can someone help me again with these math work?
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Set up an equation and solve the following problem.
nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

<u>Again</u>

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

<u>For Dave</u>

Time = \dfrac{\textrm Distance}{\textrm Speed}

So, t = \dfrac{\textrm d miles}{\textrm s miph}

Or, t = \dfrac{\textrm 210 miles}{\textrm s miph}

<u>For Kent</u>

Time = \dfrac{\textrm Distance}{\textrm Speed}

So, T = \dfrac{\textrm D miles}{\textrm S miph}

Or, T = \dfrac{\textrm 230 miles}{\textrm (s + 4) miph}

∵ Time taken by both is same

So, t = T

Or,  \dfrac{\textrm 210 miles}{\textrm s miph} = \dfrac{\textrm 230 miles}{\textrm (s + 4) miph}

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴  s = \dfrac{840}{20}

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

8 0
3 years ago
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