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3 years ago

Which of the following could represent consecutive even integers?

2 answers:

4 0

Only b. x+1, x+3 as long as x is an odd integer

a. x+1, x+2, wouldn't be consecutive even integers. If x is odd (e.g. 1), then 1+1=2 would be even but, 1+2=3 would be odd.

c. 2x, 2x+1, wouldn't be the answer. 2x will certainly be even but 2x+1 is going to be odd.

nalin [4]3 years ago

3 0

Answer:

b. x + 1, x + 3

Step-by-step explanation:

Integers : a number with no fraction part is called integers,

eg: ......-3, -2, -1, 0, 1, 2, 3......

Even integers : the integers which are multiple of 2.

Since, the difference between two consecutive even integers is always 2.

Eg : 2 and 4 are consecutive even integers.

⇒ 4 - 2 = 2.

∵ x + 2 - (x + 1) = x + 2 - x - 1 = 1,

x + 3 - (x+1) = x + 3 - x - 1 = 2,

2x + 1 - 2x = 1,

Hence, only x + 1 and x + 3 represent consecutive even integers

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Answer:

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Step-by-step explanation:

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3 years ago

For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l

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Step-by-step explanation:

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$\to \sum^n_{i=1} \frac{X_i - 2}{n} \times\sqrt{\frac{n}{2}}} \sim N(0, 1)\\\\\to \sum^n_{i=1} \frac{X_i - 2}{\sqrt{2n}} \sim N(0, 1)\\$

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Answer:

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Step-by-step explanation:

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