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kvv77 [185]
3 years ago
6

What is the 11th term of the sequence 2,8,32,128

Mathematics
2 answers:
Dmitrij [34]3 years ago
4 0
The number is multiplied by 4 down the line so 2,8,32,128,512,2048,8192,32768,131072,524288,2097152

this said, the answer is D
-BARSIC- [3]3 years ago
3 0

Answer:

Each step/term is multiplied by 4, so we get the below with each answer getting multiplied by 4:

2*4=8 (2nd term) ; 8*4=32 (3rd term) ; 32*4=128 (4th term) ; 128*4=512 (5th) ; 512*4=2,048 (6th) ; 2,048*4=8,192 (7th) ; 8,192*4=32,768 (8th) ; 32,768*4=131,072 (9th) ; 131,072*4=524,288 (10th) ; 524,288*4=2,097,152 (11th term)

Step-by-step explanation:


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