Question

What is the equation of the quadratic function in vertex form if the vertex is at (3,5) and has a leading coefficient of 2

Answer 1

Answer:

y = 2(x - 3)² + 5

Step-by-step explanation:

the equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

here (h, k) = (3, 5) and a = 2, hence

y = 2(x - 3)² + 5 ← in vertex form

Answer 2

Answer:

y-5 = 2(x-3)^2

Step-by-step explanation:

The general form of this quadratic equation is y-k = a(x-h), where (h,k) is the vertex and a is the leading coefficient.

In this case, y-5 = 2(x-3)^2.