I need help solving this. Thanks in advance.

What is the value of y 4y-3=5y+2 solv for y

Fudgin [204]

Y is 5 hope this helps

7 0

3 years ago

Read 2 more answers

Use the formula C = 5 over 9(F - 32) to write 126° F as degrees Celsius, round to the nearest tenth.

PSYCHO15rus [73]

52° is your answer :)

5 0

3 years ago

A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e

professor190 [17]

Answer:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

Step-by-step explanation:

Information given

$n=15$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =16$ represent the sample variance

$\sigma^2_0 =25$ represent the value that we want to verify

System of hypothesis

We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 25$

Alternative hypothesis: $\sigma^2$

The statistic is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And replacing we got:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

6 0

3 years ago

What is the distance apart (-6, -4.7) and (-6, 4.1)

kenny6666 [7]

Answer:

8.8

Step-by-step explanation:

Normally, to find the distance between two points, you would use the distance formula, but these two points have the same x-coordinate, meaning they will form a vertical line when connected. To find the length of a vertical line you find the distance between the y-coordinates, in this case -4.7 and 4.1. Finding the distance is the same as finding the absolute value of the difference:

|4.1 -(-4.7)|

|4.1 + 4.7|

|8.8|

8.8

7 0

3 years ago

19 * 15 hello I need help on 19 * 15 + 5 + 6 + 7 - 8 - 5

ivanzaharov [21]

Answer:

290

Step-by-step explanation:

Using PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction)

(19*15)+5+6+7-8-5=

(285)+5+6+7-8-5=

290

4 0

3 years ago