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yuradex [85]
3 years ago
13

What is the value of the expression below? (6¼) x (6¼) x (6¼) x (6¼)

Mathematics
1 answer:
matrenka [14]3 years ago
7 0

Answer:

6

Step-by-step explanation:

  • The expression 6^{\frac{1}{4}}\times 6^{\frac{1}{4}}\times6^{\frac{1}{4}}\times6^{\frac{1}{4}} can be simplified by applying  power properties.
  • Particulary, there is a property known as "power of a product property" that states that, when there is a product of a series of numbers that share the same base "a", a^n\times{a^m}\times{a^j}, the result of the multiplications is a^{m+n+j}.
  • Then,in this particular case 6^{\frac{1}{4}}\times 6^{\frac{1}{4}}\times6^{\frac{1}{4}}\times6^{\frac{1}{4}}  equals 6^{\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} }=6^1=6
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VARVARA [1.3K]


Ok, I'm going to start off saying there is probably an easier way of doing this that's right in front of my face, but I can't see it so I'm going to use Heron's formula, which is A=√[s(s-a)(s-b)(s-c)] where A is the area, s is the semiperimeter (half of the perimeter), and a, b, and c are the side lengths.

Substitute the known values into the formula:

x√10=√{[(x+x+1+2x-1)/2][({x+x+1+2x-1}/2)-x][({x+x+1+2x-1}/2)-(x+1)][({x+x+1+2x-1}/2)-(2x-1)]}

Simplify:

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<span>x√10=√[2x(2x-x)(2x-x-1)(2x-2x+1)]</span>

<span>x√10=√[2x(x)(x-1)(1)]</span>

<span>x√10=√[2x²(x-1)]</span>

<span>x√10=√(2x³-2x²)</span>

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<span>2x³-12x²=0</span>

<span>2x²(x-6)=0</span>

<span>2x²=0 or x-6=0</span>

<span>x=0 or x=6</span>

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fredd [130]

Answer:

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Step-by-step explanation:

(//answers.yahoo.com/)


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