$\bf ~\hspace{10em}\textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 8x^3-125~~ \begin{cases} 8=2\cdot 2\cdot 2\\ \qquad 2^3\\ 125=5\cdot 5\cdot 5\\ \qquad 5^3 \end{cases}\implies 2^3x^3-5^3\implies (2x)^3-5^3 \\[2em] [2x-5][(2x)^2+(2x)(5)+5^2]\implies (2x-5)(\stackrel{\stackrel{j}{\downarrow }}{4}x^2+\stackrel{\stackrel{k}{\downarrow }}{10}x+25)$

3 0

3 years ago

Teresa worked for 13 hours each day for 5 days. Then the next day she worked 9 hours. How many hours did Teresa work in all?

shtirl [24]

Answer:

Step-by-step explanation:

13 x 5 is 65. 65 + 9 is 74.

3 0

2 years ago

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Will mark as brainlist!!!!pls include steps

Goryan [66]

Step-by-step explanation:

a) 1.16× 10^-6

standard form should be less than 10. therefore, count decimal places from where the decimal point is located to the right until you reach a number less than 10 ....count the number of shifts in the above is 6 shifts to the right. when moving to the right, power will be negative.(-6)

1.157/1.16 ×10^-6

b) 6.79 × 10^10

67890000000....count till a number less than 10.there will be 10 shifts to the left. the 10 will be your power,(positive) since u r moving to the left exponent is positive

6.789/6.79 × 10^10

6 0

3 years ago

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