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3 years ago

Given: line a is parallel to line b.

Mathematics

1 answer:

mina [271]3 years ago

4 0

Answer:

Step-by-step explanation:

To solve this, we need to use the corresponding angles theorem. It states that when a transversal line cuts across 2 parallel lines, then the corresponding angles there-in are congruent or equal.

Now the pair of corresponding angles we have in this question are as follows;

1 and 5

3 and 7

2 and 6

4 and 8

All these pairs are congruent corresponding angles.

Looking at the options, option D is correct

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Can you please help me with 3 and 4

Otrada [13]

Number 3 is 1:3 but I don't know what 4 is I can't see the whole problem

3 0

3 years ago

Karen operates a hot dog stand. On Wednesday she used 9 1/3 bags of hot

trapecia [35]

<h2>Explanation:</h2>

We know that Karen operates a hot dog stand. So we have:

On Wednesday:

$\text{She used} \ 9 \frac{1}{3} \ \text{bags of hot dog buns.}$

On Thursday:

$\text{She used} \ \frac{1}{3} \ \text{as many hot dog buns as on Wednesday}$

Therefore, if x is the amount of hot dog buns she used on Thursday, then:

$x=\frac{1}{3}(9\frac{1}{3}) \\ \\ x=\frac{1}{3}\times 9+\frac{1}{3}\times \frac{1}{3} \\ \\ x=\frac{28}{9}$

Therefore, on Thursday she used 28/9 bags of hot dog buns.

6 0

3 years ago

Could someone help me, please :(

Triss [41]

Answer: $\boldsymbol{-7}m + \boldsymbol{\frac{8}{5}}$

Work Shown:

$-\frac{2}{5}(15m-4)-m\\\\-\frac{2}{5}(15m)-\frac{2}{5}(-4)-m\\\\-6m+\frac{8}{5}-m\\\\\boldsymbol{-7}m + \boldsymbol{\frac{8}{5}}$

Therefore -7 goes in the first box, and $\boldsymbol{\frac{8}{5}}$ goes in the second box.

4 0

3 years ago

Read 2 more answers

Least common multiple of 8, 30, and 75

sashaice [31]

(Not my own work.)

8 = 2 x 2 x 2
30 = ...........2 x 3 x 5 
75 = ................3 x 5 x 5 
-------------------------------------- 
....= 2 x 2 x 2 x 3 x 5 x 5 
....= 600

7 0

4 years ago

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77 students is what percent of 87 students

Natali [406]

Answer:

0.89%

Step-by-step explanation:

77/87=0.89%

4 0

3 years ago

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