0.36363636363 = 0.36363636363/1 = 3.6363636363/10 = 36.363636363/100 = 363.63636363/1000 = 3636.3636363/10000 = 36363.636363/100000 = 363636.36363/1000000 = 3636363.6363/10000000 = 36363636.363/100000000 = 363636363.63/1000000000 = 3636363636.3/10000000000 = 36363636363/100000000000 the answer is

0.36363636363 as a fraction equals 36363636363/100000000000

5 0

3 years ago

Please help me with this.

Naily [24]

Answer:

x = 15

Step-by-step explanation:

GE / JH = GF / IJ

36 / (x+3) = 60 / 30

36 / (x+3) = 2 / 1

cross-multiply:

2(x+3) = 36

2x + 6 = 36

2x = 30

x = 15

7 0

3 years ago

If $3000 is deposited in an account that pays 5% interest, what is the difference in the amount after 4 years between the amount

Triss [41]

$\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$3000\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
t=years\to &4
\end{cases}
\\\\\\
A=3000(1+0.05\cdot 4)\implies \boxed{A=3600}\\\\
-------------------------------\\\\$

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}$

$\bf A=3000\left(1+\frac{0.05}{1}\right)^{1\cdot 4}\implies A=3000(1.05)^4\implies \boxed{A=3646.51875}\\\\
-------------------------------\\\\
\stackrel{\textit{compounded interest}}{3646.51875}~~-~~\stackrel{\textit{simple interest}}{3600}$

7 0

4 years ago