Question

Find the x and y intercepts for 3x+4y-12=0

Answer 1

For any equation:
To find the x-intercepts: set y=0 and solve for x.
To find the y-intercepts: set x=0 and solve for y.

In your equation:
x-int: y=0
3x + 4(0) = 12
3x = 12 divide both sides by 3
x = 4
x-int: (4,0)

y-int: x=0
3(0) + 4y = 12
4y = 12 divide both sides by 4
y =3
y-int: (0,3)

Answer 2

Answer:

y=4/9

x=3/8

Step-by-step explanation:

if x=0

then:

3+4y-12=0

3+4y=12

4y=9

y=4/9

now if y=0

then:

3x+4-12=0

3x+4=12

3x=8

x=3/8