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4 years ago

Compare and contrast carbon to its isotopes: what is different about them and what is the same?

1 answer:

6 0

Their atomic numbers are all the same, because they all have the same number of protons. But their atomic weights are different, because they have different numbers of neutrons.

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What is the velocity of a ball dropped from a height of 150 m when it hits the ground? Take the upward direction as positive.

djyliett [7]

Answer:

The velocity of the ball when its hit the ground will be 54.22 m/sec

Explanation:

We have given height from which ball is dropped h = 150 m

Acceleration due to gravity $g=9.8m/sec^2$

As the ball is dropped so initial velocity will be zero so u = 0 m/sec

According to third equation of motion we know that $v^2=u^2+2gh$

$v^2=0^2+2\times 9.8\times 150$

$v=54.22m/sec$

So the velocity of the ball when its hit the ground will be 54.22 m/sec

7 0

3 years ago

An object is dropped from a bridge. A second object is thrown downwards 1.00 s later. They both reach the water 20.0 m below at

Deffense [45]

Answer:

$v_{o}=-14.60m/s$

Explanation:

Kinematics equation for first Object:

$y(t)=y_{o}+v_{o}t-1/2*g*t^{2}$

but:

$v_{o}=0m/s$ The initial velocity is zero

$y_{o}=20m$

it reach the water at in instant, t1, y(t)=0:

$0=y_{o}-1/2*g*t_{1}^{2}$

$t_{1}=\sqrt{2y_{o}/g}=\sqrt{2*20/9.81}=2.02s$

Kinematics equation for the second Object:

The initial velocity is zero

$y(t)=y_{o}+v_{o}t-1/2*g*t^{2}$

but:

$y_{o}=20m$

it reach the water at in instant, t2, y(t)=0. If the second object is thrown 1s later, t2=t1-1=1.02s

$0=y_{o}+v_{o}t_{2}-1/2*g*t_{2}^{2}$

$v_{o}=1/(t_{2})*(1/2*g*t_{2}^{2}-y_{o})=(1/1.02)*(1/2*9.81*1.02^{2}-20)=-14.60m/s$

The velocity is negative, because the object is thrown downwards.

6 0

3 years ago

Help Me! I’ll give you brain list btw just the first three rows if you want :’)

AleksandrR [38]

Answ

Explanation:

the adversities that the oak tree will face will add only positive effects to the atmosphere.

primarily the co2 content present in the air will diminish to provide chances for the efficiency of the human being

8 0

3 years ago

Read 2 more answers

A patricle is accelerated uniformly from rest, so that after 10 seconds it has a speed of 15m/s find its acceleration and the di

grin007 [14]

Answer:

Its acceleration is 1.5 $\frac{m}{s^{2} }$ and the distance it has covered is 150 m.

Explanation:

Acceleration is a quantity that indicates the variation in speed of a moving body as time passes. That is, acceleration relates changes in velocity with the time in which they occur.

The average acceleration is defined as the relationship between the variation or change in the speed of a mobile and the time used in said change:

$acceleration=\frac{change in speed}{time}$

In this case:

change in speed= final speed - initial speed= 15 m/s - 0 m/s= 15 m/s
time= 10 s

Replacing:

$acceleration=\frac{15 \frac{m}{s} }{10 s}$

and solving you get:

acceleration= 1.5 $\frac{m}{s^{2} }$

Speed is a quantity that expresses the relationship between the space traveled by an object and the time used for it. This is:

$speed=\frac{distance}{time}$

So the distance can be calculated as:

distance= speed* time

In this case:

speed= 15 m/s
time= 10 s

Replacing:

distance= 15 m/s* 10 s

and solving you get:

distance= 150 m

Its acceleration is 1.5 $\frac{m}{s^{2} }$ and the distance it has covered is 150 m.

8 0

3 years ago

A plastic rod rubbed with a duster attracts bits of paper becauseof a what force

likoan [24]

Its because of the static electricity.As we rub, the positive and negative charges are acquired by the plastic rod and duster.
If we bring paper bits near them, the charges possessed by the paper bits get attracted towards the charges in plastic rod.

5 0

3 years ago