Question

This homework will be due when you come to lab. Two students are pushing identical crates across a frictionless floor. The crates are initially at rest. Bing applies a horizontal force of 23 N to his crate. Bob, who is shorter than Bing, pushes on his crate at an angle of 33° below the horizontal, also with a force of 23 N. Find the ratio of the masses of the two crates if Bing’s crate is moving at twice the speed of Bob’s crate after they have traveled a distance of 33.5 m

Answer 1

Answer:

0.459

Explanation:

Energy

1. $E = \frac{1}{2} mv^{2}$

2.$E = Fx$

Combining 1 and 2:

3.$m = \frac{2Fx}{v^{2} }$

Using 3 to form the ratio:

$\frac{m_1}{m_2} = \frac{F_1}{F_2} \frac{v_2^{2} }{v_1^{2} }$

Given in the question:

$v_1 = 2v_2$

$F_2 = F_1 sin(33)$

Result:

$\frac{m_1}{m_2} = \frac{1}{4sin(33)}$