✅
Step-by-step explanation:


2x + 5y + 7x
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Combine like terms
(2x + 7x)
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9x + 5y
<h2> <u>Rectangular</u> <u>Areas</u> <u>and</u> <u>Perimeters</u></h2>
The perimeter of a rectangle is given by:

In the problem we have these data:
- Perimeter = 6 + 2 (-2x + 20)
We replace the data in the equation of the perimeter:
<h3>6 + 2 (-2x + 20) = 2 (a - 2x + 20)
</h3>
We apply distributive property:
6 - 4x + 40 = 2a - 4x + 40
6 = 2a
6 ÷ 2 = a
3 = a
⇒ Length = 3
The area of the rectangle is given by:

We have these data:
We replace the data in the equation of the area:
<h3>Area = (3) (- 2x + 20)
</h3>
We apply the distributive property and obtain:
Area = -6x + 60
<u>The expression representing the area of the rectangle will be -6x + 60</u>
<h3>I hope I've helped!</h3>
Answer:
140
Step-by-step explanation:
When working HCF and LCM problems, I like to think in terms of this little diagram:
(a [ b ) c]
It shows me one of the numbers is ab, the other is bc, the HCF is b and the LCM is abc. "a" and "c" must be relatively prime for "b" to be the HCF.
__
Here, we're given ...
b = 20
ab = 320
abc = 2240
Then ...
c = abc/(ab) = 2240/320 = 7
x = bc = 20(7) . . . . . . equivalently, x = (abc·b)/(ab) = (2240·20)/320
x = 140
Answer:
The probability that the maximum speed is at most 49 km/h is 0.8340.
Step-by-step explanation:
Let the random variable<em> </em><em>X</em> be defined as the maximum speed of a moped.
The random variable <em>X</em> is Normally distributed with mean, <em>μ</em> = 46.8 km/h and standard deviation, <em>σ</em> = 1.75 km/h.
To compute the probability of a Normally distributed random variable we first need to convert the raw score of the random variable to a standardized or <em>z</em>-score.
The formula to convert <em>X</em> into <em>z</em>-score is:

Compute the probability that the maximum speed is at most 49 km/h as follows:
Apply continuity correction:
P (X ≤ 49) = P (X < 49 - 0.50)
= P (X < 48.50)

*Use a <em>z</em>-table for the probability.
Thus, the probability that the maximum speed is at most 49 km/h is 0.8340.