Answer:
x1 = t, x2 = -t and x3 = 0
Step-by-step explanation:
Given the system of equation
x1 + x2 + x3 = 0 .... 1
x1 + x2 + 9x3 = 0 .... 2
Subtract both equation
x3 - 9x3 = 0
-8x3 = 0
x3 = 0
Substitute x3 = 0 into equation 1
x1 + x2 + 0 = 0
x1+x2 = 0
x1 = -x2
Let t = x1
t = -x2
x2 = -t
Hence x1 = t, x2 = -t and x3 = 0
The pictures is black and theres only 15 and a 1 so im gonna guess 15
The value of this equation is: 4
Answer: 4
First find the length of the diagonal of a square of side 4 inches:
d^2 = 4^2 + 4^2 = 2*4^2 = 32. Then the diagonal of the cube has length
sqrt( 32 + 4^2) = sqrt(32+16) = sqrt(48) = 4sqrt(3).
The ilne paralell to x=something is x=something else (both are constants)
slope=rise/run
x=-3
it rises infiniley and runs 0 (goes left to right 0)
slope=infinity/0=undefined
the slope is undefined
paralell lines have same slope
so the slope of a paralell line is also undefined
