To solve this problem we apply the concepts related to the Intensity, which is defined as the Power given by the object on unit area. Mathematically this is,
Where,
I = Intensity
P = Power
A = Area
Considering that a whisper is around to , then we have that
Intensity level in
Where,
Threshold intensity level
Therefore the corresponding sound intensity level is 14dB
They both have exactly the same acceleration.
Answer:
the bell has potential energy equal to,
18 x 9.8 x 45 = 7938 joules
Answer:
1 μF
Explanation:
To obtain the answer to the question, all we need to do is to calculate the equivalent capacitance of the capacitors. This can be obtained as illustrated below.
From the question given above, the following data were obtained:
Capacitor 1 (C₁) = 2 μF
Capacitor 2 (C₂) = 4 μF
Capacitor 3 (C₃) = 4 μF
Equivalent capacitance (Cₑq) =?
Cₑq = 1/C₁ + 1/C₂ + 1/C₃
Cₑq = 1/2 + 1/4 + 1/4
Cₑq = (2 + 1 + 1)/4
Cₑq = 4/4
Cₑq = 1 μF
Thus, the answer to the question is 1 μF