A spring has a spring constant of 120 newtons per meter. Calculate the elastic potential energy stored in the spring when it is
1 answer:
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Answer: 19.72m/s
Explanation:
Since we are considering the speed, the C in the formula can as well be represented with other letter V as one choses.
Answer:
Explanation:
Given that
R= 0.19 m
r= 0.28 m
I= 2.6 A
We know that
A= Area of loop
dE/dt= rate of change of electric filed
I=Displacement current
Here r>R
So A=π R²
Now by putting the values
Answer:
Option A (1.51 m) is the appropriate option.
Explanation:
The given values are:
Speed of wave,
= 362 m/s
Period,
= 4.17
Now,
⇒
then,
⇒
⇒
⇒