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3 years ago

$6000 invested at an APR a 4.4% for 20 years what is the balance in the account after 20 years

Mathematics

1 answer:

butalik [34]3 years ago

6 0

Answer:

The balance in the account after 20 years will be $11280.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

$E = P*I*t$

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

After t years, the total amount of money is:

$T = E + P$ .

In this problem

We want to find T, when $P = 6000, I = 0.044, t = 20$

The first step is find the earnings due to interest. So

$E = P*I*t = 6000*0.044*20 = 5280$

Adding to the principal to find the balance

$T = E + P = 5280 + 6000 = 11280$

The balance in the account after 20 years will be $11280.

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2 years ago

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Answer:

Part 1) see the procedure

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Part 3) $x > 9.99\ months$

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Part 1) Define a variable for the situation.

Let

x ------> the number of months

y ----> the total cost monthly for website hosting

Part 2) Write an inequality that represents the situation.

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Site B

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3 years ago

Give the properties for the equation -2x 2 - y + 10x - 7 = 0.

Sladkaya [172]

Given:

The quadratic equation is

$-2x^2-y+10x-7=0$

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

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$-2x^2-y+10x-7=0$

It can be written as

$-2x^2+10x-7=y$

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$\dfrac{-b}{2a}=\dfrac{-10}{-4}$

$\dfrac{-b}{2a}=\dfrac{5}{2}$

Putting $x=\dfrac{5}{2}$ in (i), we get

$y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7$

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On further simplification, we get

$y=\dfrac{-25+36}{2}$

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Therefore, the correct option is A.

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