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gogolik [260]
3 years ago
6

to get the the airport, jan must pay $10 for a taxi to come for to her house plus $2 for each mile they travel. write an equatio

n to describe the total number of "m" miles she should go she should go if she only has $48 to spend
Mathematics
1 answer:
ElenaW [278]3 years ago
6 0

Answer:

10+2m=48

Step-by-step explanation:

I don't really know how to explain it but making equation from world problems make sense for some reason.

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So you will have 78 $ but if he goes and donate he will probably have 0 left
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A building measuring 90m by60m is to be built. A paved area of uniform will surround the building. The area is to have an are of
Effectus [21]
A= 9000m squared and A= base(width)*hight or A=b*h so divide 9000m by 60m
9000/60=(1050) 60 120 180 240 300 360 420 480 and so on
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4 0
3 years ago
Find the values of x and y that maximize the objective function P=3x+2y for the graph. What is the maximum value?
AURORKA [14]

Answer:

(9, 0)

Step-by-step explanation:

Maximum or minimum value occurs at the Corner. The points given are (0, 8), (5, 4) and (9, 0).

Substitute (0, 8) in the objective function.

We get P = 3(0) + 2(8) = 16

Now for (x , y) = (5, 4)

P = 3(5) + 2(4) = 15 + 8 = 23

At (9, 0) we get P = 3(9) + 2(0) = 27.

Clearly, we have the maximum value at (9, 0).

And the maximum value is 27.

3 0
3 years ago
Madelyn has completed 10/20 problems. Will has completed 80% of the problems. Adam has finished 3/4 of them. Who has finished th
Vinil7 [7]

Answer:

Will has completed the Most.

Step-by-step explanation:

Madelyn has completed 50%

Adam has completed 75%

Will has completed 80%

<em>I hope this helps!!! Please Mark Me Brainliest!!!!!!</em>

6 0
3 years ago
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In a lumberjack competition, a contestant is blindfolded and then spun around 9 times. The contestant then immediately tries to
Kazeer [188]

Answer:

9.364 is the expected number of points.

we can approximate this to 10 points if we want a whole number

Step-by-step explanation:

We have these variables:

[0,5,10,15]

P(x= 0) = p(y>20)+p(y<-20) = 2p(y>20)

P(x=5) = p(-20<=y<=10)+p(10<=y<=20) = 2p(10<=y<=20)

P(x=10) = p(-10<=y<=-3)+p(3<=y<=10) = 2p(3<=y<=10)

P(x=15) = p(-3<=y<=3) = 2p(0<=y<=3)

Z = y/10

Therefore

P(x= 0) = 2(y>20)

= 2p(z>2) = 2(1-p<=2)

= 2(1-0.9772)

= 0.0456

P(x= 5)

= 2p(10<=y<=20)

= 2p(1<=z<=2)

= 2(0.9772-0.8413)

= 0.2718

P(x= 10)

= 2p(3<=y<=10)

= 2p(0.3<=z<=1)

= 2(0.8413-0.6179)

= 0.4468

P(x = 15)

= P(0.6179-0.3821)

= 0.2358

To get expected value of Y

0(0.0456)+5(0.2718)+10(0.4468)+15(0.2358)

= 1.359 + 4.468 + 3.537

= 9.364

E[Y] = 9.364

8 0
3 years ago
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