Answer: see proof below
<u>Step-by-step explanation:</u>
Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ
Use the Sum/Difference Identities:
sin(α + β) = sinα · cosβ + cosα · sinβ
cos(α - β) = cosα · cosβ + sinα · sinβ
Use the Unit circle to evaluate: sin45 = cos45 = √2/2
Use the Double Angle Identities: sin2Ф = 2sinФ · cosФ
Use the Pythagorean Identity: cos²Ф + sin²Ф = 1
<u />
<u>Proof LHS → RHS</u>
LHS: 2sin(45 + 2A) · cos(45 - 2A)
Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)
Unit Circle: 2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]
Expand: 2[(1/2)cos²2A + cos2A·sin2A + (1/2)sin²2A]
Distribute: cos²2A + 2cos2A·sin2A + sin²2A
Pythagorean Identity: 1 + 2cos2A·sin2A
Double Angle: 1 + sin4A
LHS = RHS: 1 + sin4A = 1 + sin4A 
Answer:
5 units
Step-by-step explanation:
im pretty sure i did the calculations right
Answer:
a) P value = 0.0013
b) No, it is not plausible that the silicon content of the water is no greater than it was 10 years ago
Step-by-step explanation:
The null hypothesis here is “Mean is equal to 5” while alternate hypothesis is that “Mean is greater than 5”
Given
Mean = 5, x’ = 5.4 and sigma = 1.2 and n = 85
Z = x-u’/sigma/sqrt n
Substituting the given values, we get –
Z = 3.02
A) P value = 0.0013 which is less than 0.05 and thus we will reject the null hypothesis
B) There is enough evidence to reject the null hypothesis
Answer:
m∠KML+m∠MLK=m∠JKM
m∠KML+m∠MLK=m∠JKM
Step-by-step explanation:
we know that
The sum of the interior angles of triangle must be equal to 180 degrees
m∠KML+m∠MLK+m∠MKL=180° -----> equation A
m∠JKM+m∠MKL=180° -----> by supplementary angles (form a linear pair)
m∠MKL=180°-m∠JKM ----> equation B
substitute equation B in equation A
m∠KML+m∠MLK+(180°-m∠JKM)=180°
m∠KML+m∠MLK=m∠JKM
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