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Alex Ar [27]
3 years ago
5

The least number thats is a multiple of two or more whole numbers is​

Mathematics
1 answer:
Eduardwww [97]3 years ago
6 0

Answer:

The least number that's is a multiple of two or more whole numbers is​ the Greatest Common Factor (G.C.F.)

Step-by-step explanation:

A common multiple is a number that is a multiple of two or more numbers. Common multiples of 2 and 3 are 0, 6, 12, 18, ... The least common multiple (LCM) of two numbers is the smallest number (excluding zero) that is a multiple of both of the numbers.

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If the variance is 28 kg2 what is the standard deviation?
ikadub [295]

Answer:

The standard deviation is 5.29 kg.

Step-by-step explanation:

The standard deviation is the square root of the variance. Mathematically, we have that:

S(X) = \sqrt{V(X)}

In this problem, we have that:

V(X) = 28

So

S(X) = \sqrt{V(X)}

S(X) = \sqrt{28}

S(X) = 5.29

The standard deviation is 5.29 kg.

7 0
3 years ago
Answer the linear inequality
PolarNik [594]
Substitute x-values into x.
e.g. y>-3.5x + 2
let x be 1...
thus, y>-3.5(1) + 2
y> -1.5 or y<1.5
another e.g. let x be 2.
y> -3.5(2) + 2
y> -4.4 or y<4.4
And so forth. pluck in these coordinates into you graph and sketch a line through the points.
NOTE: < in my explanation is equivalent to less than or equal to. same goes to >… greater than or equal to.

I hope you followed through. Good luck!

4 0
3 years ago
(PLEASE HELP ASAP!!)
AysviL [449]

I believe the answer is 21. I can tell you how I got the answer if you want.

7 0
3 years ago
Read 2 more answers
What is 1+1?????????????????????​
ivolga24 [154]
It is 2 lol also use a calculator it’s wayyy easier this is like the easiest equation every
3 0
2 years ago
Find all the real zeros of <br><br> f(x)=3x^3-9x^2+3x-9 <br><br><br> Can someone help me please
vaieri [72.5K]

Answer:

x=0,3

Step-by-step explanation:

start by dividing every term by 3

x^3-3x^2+x-3

group into 2 terms

(x^3-3x^2)+(x-3)

simplify as much as you can

x^2(x-3)+(x-3)

combine terms

(x^2)(x-3)

x=3, 0

4 0
3 years ago
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