Answer:
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Step-by-step explanation:
brainlest if helped
We can solve this problem by using the distance formula. The distance formula is:
We can now put in values and solve.
![\sqrt{(-6-0)^{2} + (7-8)^{2}}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%28-6-0%29%5E%7B2%7D%20%2B%20%287-8%29%5E%7B2%7D%7D%20%20%20%20%20%20)
![\sqrt{36 + 1}](https://tex.z-dn.net/?f=%20%5Csqrt%7B36%20%2B%201%7D%20%20%20%20%20%20)
![\sqrt{37}](https://tex.z-dn.net/?f=%20%5Csqrt%7B37%7D%20%20%20%20%20%20)
Answer:
see explanation
Step-by-step explanation:
Given a quadratic in standard form
f(x) = ax² + bx + c : a ≠ 0
• If a > 0 then minimum value U
• If a < 0 then maximum value ∩
f(x) = x² - 4x + 1 ← is in standard form
with a = 1 > 0
Thus f(x) = x² - 4x + 1 has a minimum value U
How do you simplify i^68 = One