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AfilCa [17]
3 years ago
10

13. The figure below shows three identical squares ABCD, CEFG and CJIH

Mathematics
1 answer:
Maru [420]3 years ago
7 0

Step-by-step explanation:

DCE²+GCH²+X²=180°

40²+27²+X²=180°

x²=2329-180°

x=√2149

x=49//

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BC = x + 14, AB = x + 10, AC = 22
irinina [24]

ab = x + 10 \\  bc = x  + 14 \\ ac = 22  \\ (x + 10) + (x + 14) = 22 \\ x + x + 10 + 14 = 22 \\ 2x + 24 = 22 \\ 2x = 22 - 24  \\ 2x =  - 2 \\ x =  \frac{ -2}{2}  \\ x =  - 1

4 0
3 years ago
Please help ASAP URGENT Will mark Brianlest
PIT_PIT [208]

Answer:

A

Step-by-step explanation:

i used the process of elimination and got rid of answers that didnt make sense but based on the info given i could tell that x was 5 months because of where the point of 5 is on the graph

8 0
3 years ago
Read 2 more answers
Can someone help me please? Maybe give the answers?<br><br><br><br><br><br>Thank you.
pishuonlain [190]

Answer:

Finding the missing number is fairly simple and can be done in a few short steps. I will show you using the 21 / __ fraction.

First, divide the included number by its corresponding number in the original fraction.

21 ÷ 3 = 7

To find what the denominator of this would be, multiply 4 by 7.

4 * 7 = 28

The fraction would be 21 / 28.

This works with both numerators and denominators. If you need more of the answers just ask in the comments.


7 0
3 years ago
Read 2 more answers
A polynomial function upper P left parenthesis x right parenthesis with rational coefficients has the given roots. Find two addi
mylen [45]

Given that a polynomial function P(x) has rational coefficients.

Two roots are already given which are i and 7+8i,

Now we have to find two additional roots of P(x)=0

Given roots i and 7+8i are complex roots and we know that complex roots always occur in conjugate pairs so that means conjugate of given roots will also be the roots.

conjugate of a+bi is given by a-bi

So using that logic, conjugate of i is i

also conjugate of 7+8i is 7-8i

Hence final answer for the remaining roots are (-i) and (7-8i).

5 0
3 years ago
What is the equation of the quadratic graph with a focus of (4, −3) and a directrix of y = −6?
Artyom0805 [142]

Answer:

y=\frac{1}{6} (x-4)-\frac{9}{2}

Step-by-step explanation:

∵ The quadratic equation form is :

y = [1/2(b - k)] (x - a)² + (b + k)/2

Where (a , b) is the focus and directrix y = k

∵ The focus is (4 , -3) and directix is y = -6

∵ y=\frac{1}{2(-3-(-6))} (x-4)^{2}+\frac{(-3)+(-6)}{2}

∴ y=\frac{1}{6} (x - 4)^{2}+\frac{-9}{2}

∴ y=\frac{1}{6} (x-4)-\frac{9}{2}

another way:

Assume that (x , y) is the general point on the parabola

∵ The distance between the directrix and (x , y) = the distance between the focus and (x , y)

By using the distance rule:

∵ (y - -6)² = (x - 4)² + (y - -3)² ⇒ (y + 6)² = (x - 4)² + (y + 3)

∴ y² + 12y + 36 = (x - 4)² + y² + 6y + 9

∴ 12y - 6y = (x - 4)² + 9 - 36

∴ 6y = (x - 4)² - 27 ⇒ ÷ 6

∴ y = 1/6 (x - 4)² - 9/2

4 0
3 years ago
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