Answer:
The electric field intensity is <u>30000 N/C.</u>
Explanation:
Given:
Magnitude of the point charge is,
Distance of the given point from the point charge is,
Electric field intensity is directly proportional to the magnitude of point charge and inversely proportional to the square of the distance of the point and the given charge.
Therefore, electric field intensity 'E' at a distance of 'd' from a point charge 'q' is given as:
Plug in . Solve for 'E'.
Therefore, the electric field intensity at a point 3 cm from the point charge is 30000 N/C.
1) G.mars= 9.8x(1/3)=3.26
Vi=10 m/s , T=12 sec
Dis. = Vi(t)+1/2(g)(t)^2
(10)(12)+1/2(3.26)(12)^2= 354.72
2)V=500 m/s
Hmax= v^/2(g) = 500^2/2(9.8) = 12755.1
Answer:
C 340 m
Explanation:
may i be marked brainliest?
This would prove that gold is an <em>element</em>. No matter how far down you
examine it, you never find any particles of anything except gold.
An example of a different case is salt.
-- Imagine you had a block of salt and decided to cut it in half.
-- If you repeated this process, then eventually, at some point, you'd have
a tiny particle of salt in front of you, just like before. BUT ...
-- Just as you were getting ready to cut this one in half, you'd notice that this
particle of salt is different. It's one atom of sodium stuck to one atom of chlorine,
and if you cut it in half, you would not have ANY salt. <span />
This would prove that salt is a <em><u>compound</u></em>, made of atoms of two or more elements.
Answer:
Explanation:
a ) If x be the position of n the bright fringe on the screen , following formula holds .
x = n (λD / d) ; λ is wave length , D is screen distance and d is slit separation .
If we increase the value of λ or wave length, x will increase so central fringe along with all the fringes will shift away from the centre .
If we increase the value of D or screen distance , it will also increase x , so fringes along with central fringe will shift away from the center.
b ) Fringes ,whether bright or dark , both shift together , either towards or away from the center .
So to move the dark spots towards the center , we need to do the opposite to what we did in the first case , ie decrease the wavelength or decrease the screen distance .