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maw [93]
2 years ago
14

what will be the final temperature is 0.05kg water at 0 degree centigrade is added to 0.25kg pf water at 90 degree centigrade sp

ecific heat capacity of water is 4200J/kgk​
Physics
1 answer:
scoray [572]2 years ago
7 0

Q in = Q out

0.25 x 4200 x (90-t)=0.05 x 4200 x (t-0)

1050 (90-t)=210t

94500-1050t=210t

94500=1260t

t=75°

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Answer:

a

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Explanation:

From the question we are told that

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 Generally this workdone  by friction is also mathematically represented as

           W = - \mu *  m *  g * d

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=>       \mu =  - \frac{0.5 *  ( v_f^2 - v^2 )}{g * d }

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