y = y0 +v0*t +0.5at^2
where y0 = initial vertical position = 22m
y = final vertical position = 0m
v0 = initial vertical velocity = 0 m/s
a = acceleration = -9.8 m/s^2
t = time in seconds
0 = 22 +0*t + 0.5(-9.8)t^2
t^2 = 22/4.9 = 4.49 s^2
t = 2.12 s
So it traveled 35m in 2.12 s
the horizontal distance traveled is determined by:
x = x0 +v0*t +0.5at^2
but here a in the horizontal direction is 0 m/s^2
and v0 is in the velocity in the horizontal direction in this equation
35 m = 0 +v0*t
35 m = v0(2.12 s)
v0 = 16.5 m/s
So the ball was kicked 16.5 m/s in the horizontal direction
Answer:
Explanation:
If the distance () and speed (), measured in centimeters and centimeters per hour, respectively, are directly proportional to each other, then each set of values must observe the following relationship:
(Eq. 1)
Where is the proportionality constant, measured in .
If we know that , , , , and , then the constant of proportionality for each pair is:
As , we conclude that correct equation is .
Answer:
2500 N/C
Explanation:
Electric Field: This can be defined as the the force per unit charge in an electric field. The S.I unit is N/C
V = E.r ....................... Equation 1
Where V = Electric potential, E = Electric Field, r = Distance between the two parallel plate,
Make E the subject of the equation,
E = V/r .................... Equation 2
Given: V = 10 V, r = 4.00 mm = (4/1000) m = 0.004 m.
Substitute into equation 2
E = 10/0.004
E = 2500 N/C
Hence the electric field = 2500 N/C
Answer:
1.336 m
Explanation:
q = - 3.77 micro C at y = 0 m
Q = - 4.92 micro C at y = 2.86176 m
Let the electric field is zero at P which is at a distance y from origin.
Electric field at P due to q is equal to the electric field at P due to Q.
2.86176 - y = 1.142 y
2.142 y = 2.86176
y = 1.336 m
Thus, the electric field is zero at y = 1.336 m.
Resistance typically opposes flow of current.
When the Resistance is increased, the current would be reduced, but when the Resistance is reduced, the current would be increased in the circuit.