Pretty shore its nose and mouth
Answer:
Explanation:
(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m/150s=2ms^−1. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m.
Hence, his average velocity is 300m/150s=2ms^−1
(b) Then it is given that he turns back and points B and jogs on the same road but in the opposite direction for a time interval for 1 minute and covers a distance of 100m.If we consider the whole motion of Joseph, i.e. from point A to point C, then he covers a total distance of 300m+100m=400m. And he covers this total distance in a time interval of 2.5min+1min=3.5min=210s.
Therefore, his average speed for this journey is 400m210s=1.9ms−1.
For the same journey is displacement is equal to the distance between the points A and C,i.e. 300m−100m=200m.
Hence, his average velocity for this case is 200m/210s=0.95ms^−1
Answer:
U1 = U2 since the temperature inside the balloon does not change
Q1 - W1 = Q2 - W2
Work done by the balloon = W2 - W1 (on the environment)
W2 - W1 = Q2 - Q1 = 75 J heat put into balloon
So the balloon does 75 J on the environment
Answer:
here we can say that acceleration of the satellite is same as the gravitational field due to Earth at that location
Explanation:
As we know that gravitational field is defined as the force experienced by the satellite per unit of mass
so we will have
now in order to find the acceleration of the satellite we know by Newton's II law
so we will have
so here we can say that acceleration of the satellite is same as the gravitational field due to Earth at that location
Answer:
7 MW
Explanation:
mass of helicopter, m = 12 Mg = 12000
volume of water in bucket, V = 5 m³
diameter of blade, D = 14 m
density of water, d = 1000 kg/m³
density of air, d' = 1.23 kg/m³
The weight of water and the helicopter is balanced by the thrust produced by the rotor blade of the helicopter.
So, force
F = m x g + V x d x g
F = 12000 x 9.8 + 5 x 1000 x 9.8
F = 166600 N
Let initially the velocity of blade is v
v = 41.96 m/
Power of the helicopter, P = Force x velocity
P = 166600 x 41.96
P = 7 x 10^6 Watt
P = 7 MW