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Natalija [7]
3 years ago
14

When balanced forces act on an object, what type of motion can the object have?

Mathematics
1 answer:
maks197457 [2]3 years ago
4 0

Answer:

Forces that are equal in size but opposite in direction are called balanced forces. Balanced forces do not cause a change in the motion of objects. Forces that cause a change in motion of objects are called unbalanced forces. Unbalanced forces can change the motion of an object in two ways.

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Elza [17]

Answer: b: s=n x 23

Step-by-step explanation:

When looking at the coordinates on the graph, each point increases by 23. 23 is multiplied by the number day it is (n)

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3.000x10^2+6.000x10^5
hjlf
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Lorico [155]

Answer:

a=502 +1.28*81=605.68

So the value of height that separates the bottom 90% of data from the top 10% is 605.68.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(502,81)  

Where \mu=502 and \sigma=81

We want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=502 +1.28*81=605.68

So the value of height that separates the bottom 90% of data from the top 10% is 605.68.  

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Answer:

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Step-by-step explanation:

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