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3 years ago

13

Max bought tools costing $75.He made a $30 down payment and plans to pay off the rest in 5 months .How much will Max's monthly p

ayments be

1 answer:

Savatey [412]3 years ago

8 0

Max will have to make a monthly payment of $9

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Claire deposited $500 into a savings account that earns 2.5% annual simple interest. If she keeps this amount in the account for

Snezhnost [94]

Answer:

Claire will earn $25 in interest after 2 years.

7 0

3 years ago

Simplify the expression: (4 − 7i) + (1 − 2i).<br><br> 3 − 9i<br> 3 − 5i<br> 5 − 9i<br> 5 − 5i

motikmotik

Answer:

5-9i

Step-by-step explanation:

If you add the 4 and 1 you get 5, and if you add -7i and -2i since they are both negative, they stay negative, so you get -9i. So the answer is 5-9i.

6 0

3 years ago

Chrissy wants to spend at most $45 on dinner. If she bought an entree for $20 and she wants to buy mini appetizers for $3 each,

Sever21 [200]

Answer:

Step-by-step explanation:

Chrissy can buy 8 mini appetizers.......because

45 - 20 = 25

25 divide 3 = 8.3333333333333 so the most she can buy is 8..

:)

8 0

3 years ago

Help what’s the answer

-BARSIC- [3]

Would be x^2-5-6 so the 0s would be (x-6)(x+1) so 6 and -1

7 0

2 years ago

A researcher surveyed 150 high school students and found that 68% played a musical insturment. What would be a reasonable range

maria [59]

Answer:

The reasonable range for the population mean is (61%, 75%).

Step-by-step explanation:

The interval estimate of a population parameter is an interval of values that consist of the values within which the true value of the parameter lies with a certain probability.

The mean of the sampling distribution of sample proportion is, $\hat p$ .

One of the best interval estimate of population proportion is the 95% confidence interval for proportion,

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Given:

n = 150

$\hat p$ = 0.68

The critical value of <em>z</em> for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the 95% confidence interval for proportion as follows:

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.68\pm1.96\sqrt{\frac{0.68(1-0.68)}{150}}\\\\=0.68\pm 0.0747\\\\=(0.6053, 0.7547)\\\\\approx (0.61, 0.75)$

Thus, the reasonable range for the population mean is (61%, 75%).

5 0

3 years ago