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3 years ago

How can utilities be made safer to avoid damage during and after earthquakes

Physics

2 answers:

DIA [1.3K]3 years ago

5 0

wrap something soft around them. Think about how you get your packages if something gets shipped to you.

Arte-miy333 [17]3 years ago

3 0

Usually, much of the destruction throughout earthquakes occur from flooding and fires created by damaged utilities. Gas channels or water pipes can be crushed throughout the earthquakes. Adjustable brackets in the blocks can protect them of damage and automated shut-off devices can be employed to prevent gas and water leakage.

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1.what is the purpose of a electric load?

Liono4ka [1.6K]

Electric load holds onto electricity
Power source shoots electricity out
Conductors allow electricity to pass through

7 0

3 years ago

what is the momentum of a 10000kg truck whose velocity is 20m/s and what velocity must a 5000kg truck attain in order to have th

Mice21 [21]

Answer:

40m/s

Explanation:

P=mv

m1v1=m2v2

(20)(10000)=(5000)v

200000=5000(v)

v=40m/s

4 0

4 years ago

Read 2 more answers

A crate on a motorized cart starts from rest and moves with a constant eastward acceleration of a = 2.20 m/s2. A worker assists

trasher [3.6K]

Answer:

Explanation:

Given

acceleration a =2.2 m/s^2

Force F(t) is given by

F(t)=5.40 t N/s

Power supplied by this force at different time t is given by

Power $=F\cdot v$

velocity at any instant t is given by

v=at

Power $=5.40 t\cdot 2.2 t$

Power $=11.88 t^2$

at t=1 s

Power =11.88 W

at t=2 s

Power $=11.88\times 4=47.52$

at =4 s

Power $=11.88 \times 16=190.08$

6 0

3 years ago

What acceleration of a 45 kg mass pushed with 15 N of force?

Hitman42 [59]

Explanation:

Fnet = ma.

Assume that there is no resistance acting on the mass. Therefore a = 15N / 45kg = 0.33N/kg or 0.33m/s^2.

3 0

4 years ago

A pair of electrically charged objects attract each other with a force of 4 N when they are a distance of 3 m apart. If their ch

Rainbow [258]

Answer:

1 N

Explanation:

From coulomb's law,

The force of attraction between two charges is inversely proportional to the square of the distance between the charges.

From the question,

Assuming the charges are the same in both case,

F ∝ /r²....................... Equation 1

Fr² = k

F'r'² = Fr²........................... Equation 2

Where F' = First Force, r'² = First distance, F = second force, r² = second distance.

make F the subject of the equation,

F = F'r'²/r².................... Equation 3

Given: F' = 4 N, r' = 3 m, r = 6 m

Substitute into equation 3

F = 4(3²)/6²

F = 36/36

F = 1 N

7 0

3 years ago