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Anton [14]
3 years ago
15

To calculate the speed of an object traveling down a zip line, you must know

Physics
1 answer:
Naya [18.7K]3 years ago
4 0

Answer:

B. the distance traveled over a period of time.

Explanation:

v = d/t

v = velocity

d = distance

t = time

You might be interested in
A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.50 Ω is in a 1.0 mT magnetic field, with the coil orien
n200080 [17]

Answer:

The voltage across the capacitor is 1.57 V.

Explanation:

Given that,

Number of turns = 10

Diameter = 1.0 cm

Resistance = 0.50 Ω

Capacitor = 1.0μ F

Magnetic field = 1.0 mT

We need to calculate the flux

Using formula of flux

\phi=NBA

Put the value into the formula

\phi=10\times1.0\times10^{-3}\times\pi\times(0.5\times10^{-2})^2

\phi=7.85\times10^{-7}\ Tm^2

We need to calculate the induced emf

Using formula of induced emf

\epsilon=\dfrac{d\phi}{dt}

Put the value into the formula

\epsilon=\dfrac{7.85\times10^{-7}}{dt}

Put the value of emf from ohm's law

\epsilon =IR

IR=\dfrac{7.85\times10^{-7}}{dt}

Idt=\dfrac{7.85\times10^{-7}}{R}

Idt=\dfrac{7.85\times10^{-7}}{0.50}

Idt=0.00000157=1.57\times10^{-6}\ C

We know that,

Idt=dq

dq=1.57\times10^{-6}\ C

We need to calculate the voltage across the capacitor

Using formula of charge

dq=C dV

dV=\dfrac{dq}{C}

Put the value into the formula

dV=\dfrac{1.57\times10^{-6}}{1.0\times10^{-6}}

dV=1.57\ V

Hence, The voltage across the capacitor is 1.57 V.

5 0
3 years ago
What would be the mass of a sample containing 0.7 mol of pure tungsten?. . 0.04 g. . 51.8 g. . 128.7 g. . 262.6 g.
mojhsa [17]
There are several information's of immense importance already given in the question. The answer to the question can be easily determined using those available information's. 

Mr of pure tungsten = 183.84
Mass of tungsten = Mole * Mr
                             = 0.7 * 183.84
                             = 128.7 gm
From the above deduction, it can be concluded that the correct option among all the options that are given in the question is the third option or the penultimate option.
4 0
3 years ago
Read 2 more answers
What do we call a change in the car’s speed or direction?<br><br><br> Help!!
zhuklara [117]
The answer for this question is acceleration
8 0
4 years ago
Read 2 more answers
On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 92.6 cm and diameter 2.95 cm fr
slavikrds [6]

Answer:

48.4293354946 N

Yes

Explanation:

d = Diameter of rod = 2.95 cm

h = Length of rod = 92.6 cm

\rho = Density of rod = 7800 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

Volume of rod

V=\dfrac{1}{4}\pi d^2h\\\Rightarrow V=\dfrac{1}{4}\times \pi\times (2.95\times 10^{-2})^2\times 92.6\times 10^{-2}

Mass is given by

m=\rho V\\\Rightarrow m=7800\times \dfrac{1}{4}\times \pi\times (2.95\times 10^{-2})^2\times 92.6\times 10^{-2}\\\Rightarrow m=4.93673144695\ kg

Weight is given by

W=mg\\\Rightarrow W=4.93673144695\times 9.81\\\Rightarrow W=48.4293354946\ N

The weight of the rod is 48.4293354946 N

The mass of the rod is 4.93673144695 kg which is light. So, I will be able to carry the rod without a cart.

7 0
3 years ago
A closed box has two metal terminals a and b. The inside of the box contains an unknown emf 8 in series with a resistance R. Whe
Lelu [443]

Answer:

The value of \epsilon and R are 12.9 ohm and 2.6 V.

Explanation:

Given that,

Potential difference = 22.0 V

Current = 1.50 A

If this potential difference is reversed,

Then the current = 1.90 A

In forward direction

The net emf is

\epsilon=(\epsilon+22.0)\ V

The net current is

I=\dfrac{V}{R}

1.50=\dfrac{\epsilon+22.0}{R}...(I)

In reverse direction

1.90=\dfrac{22.0-\epsilon}{R}...(II)

From equation (I) and (II)

\epsilon =2.6\ V

R = 12.9\ Omega

Hence, The value of \epsilon and R are 12.9 ohm and 2.6 V.

8 0
4 years ago
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