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3 years ago

Juan has blood type A, Lilly has blood type AB, and Aaron has blood type O. Is this relation a function? Explain.

Mathematics

1 answer:

nexus9112 [7]3 years ago

3 0

Answer: Yes, this relation is function.

Step-by-step explanation:

A relation is called function if each input has unique output.

It is given that, Juan has blood type A, Lilly has blood type AB, and Aaron has blood type O.

Juan is related to blood type A.

Lilly is related to blood type AB.

Aaron is related to blood type O.

Here, each input has unique output because here each person has unique blood group.

Therefore, this relation is a function.

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3 years ago

Beth bought 15 tickets to a movie, where adult tickets cost $6.00 and

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Answer:

B. a + s = 15

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Step-by-step explanation:

The two equations you want to write are for the two resources, tickets and dollars. We want to know the numbers of adult and senior tickets, so we assign the variables "a" and "s" to those numbers, respectively. We need to keep the meaning of these variables in mind as we write the equations.

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In summary, the two equations are ...

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3 years ago

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elena-14-01-66 [18.8K]

Answer:

$\begin{gathered} sin(\theta)=\frac{-\sqrt{7}}{4} \\ cos(\theta)=-\frac{3}{4} \\ tan(\theta)=\frac{\sqrt{7}}{3} \\ csc(\theta)=-\frac{4}{\sqrt{7}} \\ sec(\theta)=-\frac{4}{3} \\ cot(\theta)=\frac{3}{\sqrt{7}} \end{gathered}$

Step-by-step explanation:

If theta is in the third quadrant, draw the diagram to easily identify the other trigonometric relations:

Solve for the missing leg of the triangle, using the Pythagorean theorem:

$\begin{gathered} \text{ adjacent}^2+\text{ opposite}^2=\text{ hypotenuse}^2 \\ -3^2+\text{ opposite}^2=4^2 \\ \text{ opposite=}\sqrt{16-9} \\ \text{ opposite=}\sqrt{7} \end{gathered}$

Therefore, for the trigonometric relationships:

$\begin{gathered} \text{ sin\lparen}\theta)=\frac{opposite}{hypotenuse} \\ \text{ cos\lparen}\theta)=\frac{adjacent}{hypotenuse} \\ tan(\theta)=\frac{opposite}{adjacent} \\ csc(\theta)=\frac{hypotenuse}{opposite} \\ sec(\theta)=\frac{hypotenuse}{adjacent} \\ cot(\theta)=\frac{adjacent}{opposite} \end{gathered}$

Now, substitute and solve for the relations:

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