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3 years ago

Is -0.06006000600006... rational or irrational?

2 answers:

4 0

It’s an irrational number because it doesn’t repeat or terminate. It can’t be turned into a fraction, therefore it’s irrational.

jok3333 [9.3K]3 years ago

3 0

This is an irrational number

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For each of the following vector fields F , decide whether it is conservative or not by computing curl F . Type in a potential f

Phantasy [73]

The key idea is that, if a vector field is conservative, then it has curl 0. Equivalently, if the curl is not 0, then the field is not conservative. But if we find that the curl is 0, that on its own doesn't mean the field is conservative.

$\mathrm{curl}\vec F=\dfrac{\partial(5x+10y)}{\partial x}-\dfrac{\partial(-6x+5y)}{\partial y}=5-5=0$

We want to find $f$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=-6x+5y\implies f(x,y)=-3x^2+5xy+g(y)$

$\dfrac{\partial f}{\partial y}=5x+10y=5x+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=10y\implies g(y)=5y^2+C$

$\implies\boxed{f(x,y)=-3x^2+5xy+5y^2+C}$

so $\vec F$ is conservative.

$\mathrm{curl}\vec F=\left(\dfrac{\partial(-2y)}{\partial z}-\dfrac{\partial(1)}{\partial y}\right)\vec\imath+\left(\dfrac{\partial(-3x)}{\partial z}-\dfrac{\partial(1)}{\partial z}\right)\vec\jmath+\left(\dfrac{\partial(-2y)}{\partial x}-\dfrac{\partial(-3x)}{\partial y}\right)\vec k=\vec0$

Then

$\dfrac{\partial f}{\partial x}=-3x\implies f(x,y,z)=-\dfrac32x^2+g(y,z)$

$\dfrac{\partial f}{\partial y}=-2y=\dfrac{\partial g}{\partial y}\implies g(y,z)=-y^2+h(y)$

$\dfrac{\partial f}{\partial z}=1=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=z+C$

$\implies\boxed{f(x,y,z)=-\dfrac32x^2-y^2+z+C}$

so $\vec F$ is conservative.

$\mathrm{curl}\vec F=\dfrac{\partial(10y-3x\cos y)}{\partial x}-\dfrac{\partial(-\sin y)}{\partial y}=-3\cos y+\cos y=-2\cos y\neq0$

so $\vec F$ is not conservative.

$\mathrm{curl}\vec F=\left(\dfrac{\partial(5y^2)}{\partial z}-\dfrac{\partial(5z^2)}{\partial y}\right)\vec\imath+\left(\dfrac{\partial(-3x^2)}{\partial z}-\dfrac{\partial(5z^2)}{\partial x}\right)\vec\jmath+\left(\dfrac{\partial(5y^2)}{\partial x}-\dfrac{\partial(-3x^2)}{\partial y}\right)\vec k=\vec0$

Then

$\dfrac{\partial f}{\partial x}=-3x^2\implies f(x,y,z)=-x^3+g(y,z)$

$\dfrac{\partial f}{\partial y}=5y^2=\dfrac{\partial g}{\partial y}\implies g(y,z)=\dfrac53y^3+h(z)$

$\dfrac{\partial f}{\partial z}=5z^2=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=\dfrac53z^3+C$

$\implies\boxed{f(x,y,z)=-x^3+\dfrac53y^3+\dfrac53z^3+C}$

so $\vec F$ is conservative.

4 0

3 years ago

The sum of two integers is 6 and the difference between the numbers is 40. Find the numbers

nevsk [136]

Set up a system of equations.

X+y=6
Y-x =40

Substitution method.

Y=6-x

(6-x)-x =40
6-2x=40
-2x=34
X= -17

Plug it back into the equation.
-17+y=6
Y=33

(-17,33) is one of the possible answers.

8 0

3 years ago

Read 2 more answers

Which figure is described below the locus of points in a plane equidistant between x=4 and x=6

Oksi-84 [34.3K]

Answer:

The picture is black

Step-by-step explanation:

Dbddndnddnskskskssndjd

3 0

3 years ago

Which values of a, b, and c correctly represent the answer in simplest form? 3 =a O a=38.0= 14.0=1 a=1.0= 14.C = 38 O a= 1.5=7.C

katrin [286]

Answer:

The answer could be A) or D) because the zero acts as a place holder. Its a little easier to derive it if you have a bigger decimal

Step-by-step explanation:

5 0

3 years ago

A photo is 15 centimeters high and 9 centimeters wide. Mikael wants to proportionately shrink it so its height is 6 centimeters

gtnhenbr [62]

Answer:

6:3.6

Step-by-step explanation:

The hight of the photo=15

so,15=6

15 :- 2.5=6

9 divided by 2.6= 3.6

therefour, the answer will be 6:3.6

8 0

3 years ago

Is -0.06006000600006... rational or irrational?​

Is -0.06006000600006... rational or irrational?