Find the solution set for this equation. a2 + a=0 Separate the two values with a comma.

Mathematics

1 answer:

ira [324]2 years ago

6 0

Answer:

a = 0,-1

Step-by-step explanation:

a^2 + a=0

Factor out an a

a(a+1) =0

Using the zero product property

a=0 a+1 =0

a=0 a= -1

You might be interested in

If L=√(x^2+y^2), dx/dt =-4, dy/dt=3, find dL/dt when x=4 and y=3

yulyashka [42]

Hello,

$L=\sqrt{x^2+y^2} \\\\\dfrac{dx}{dt}=-4\\\\\dfrac{dy}{dt}=3\\\\x=4, y=3\\\\\dfrac{\partial L} {\partial x} =\dfrac{x}{\sqrt{x^2+y^2}} \\\\\dfrac{\partial L} {\partial y} =\dfrac{y}{\sqrt{x^2+y^2}} \\\\\dfrac{dL}{dt} =\dfrac{\partial L} {\partial x}*\dfrac{dx}{dt}+\dfrac{\partial L} {\partial y}*\dfrac{dy}{dt}\\\\=-4*\frac{-4}{\sqrt{4^2+3^2}} +3*\frac{3}{\sqrt{4^2+3^2}}\\\\=\dfrac{16}{5} +\dfrac{9}{5} \\\\=5\\$

5 0

2 years ago

Someone please help me this is due tomorrow!!!

Murljashka [212]

Let me know if you can see this photo

3 0

2 years ago

How to solve for the answer

yarga [219]

A.step 1 because it should be x^2 not 2x

3 0

3 years ago

Use the graph of f(x) below to estimate the value of f '(3):

klio [65]

Well, looking at the graph, notice, its vertex is at 0,9, and it passes through the points -3,0 and 3,0, so hmm let's use 3,0, to get the equation of f(x)

$\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------$

$\bf vertex~(0,9)~
\begin{cases}
h=0\\
k=9
\end{cases}\implies y=a(x-0)^2+9
\\\\\\
\textit{we also know that }
\begin{cases}
x=3\\
y=0
\end{cases}\implies 0=a(3-0)^2+9
\\\\\\
-9=9a\implies \cfrac{-9}{9}=a\implies -1=a\quad thus\quad \boxed{y=-x^2+9}
\\\\\\
\left. \cfrac{dy}{dx}=-2x \right|_{x=3}\implies -6$

3 0

3 years ago

Read 2 more answers

What is the answer to this c=15×+2000<br> r=35x

Slav-nsk [51]

C=<span>30000
and the other one do u want me to solve for x or r?</span>

6 0

3 years ago