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LiRa [457]
3 years ago
13

The stack ADT may be implemented with

Computers and Technology
1 answer:
Masteriza [31]3 years ago
4 0

Answer: (c)All others answers

Explanation: Stack ADT is the group of the objects that are present  to work according to the last in first out strategy for the abstract data types. It works on the insertions and deletion of the elements that is referred as the push and pop action.

The ADT stacks can works with arrays, links list as well as vectors for the operation .Therefore, the correct option is option(c)

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Write a program to prepare the monthly charge account statement for a customer of CS CARD International, a credit card company.
WITCHER [35]

Answer:

import java.util.*;

import java.text.*;

class CreditCardBill

{

public static void main(String[] args)

{

Scanner sc = new Scanner(System.in);

NumberFormat defaultFormat = NumberFormat.getCurrencyInstance(Locale.US);

System.out.println("CS Card International Statement");

System.out.println("===============================");

System.out.print("Previous Balance: $");

double prevBalance = sc.nextDouble();

System.out.print("Additional Charges: $");

double addCharges = sc.nextDouble();

double interest;

if(prevBalance == 0)

interest = 0;

else

interest = (prevBalance + addCharges) * 0.02;

System.out.println("Interest: "+defaultFormat.format(interest));

double newBalance = prevBalance + addCharges + interest;

System.out.println("New Balance: "+defaultFormat.format(newBalance));

double minPayment;

if(newBalance < 50)

minPayment = newBalance;

else if(newBalance <= 300)

minPayment = 50.00;

else

minPayment = newBalance * 0.2;

System.out.println("Minimum Payment: "+defaultFormat.format(minPayment));

}

}

5 0
3 years ago
Technology question.
Gnoma [55]

You should select the text by clicking and holding the mouse at the beginning of the text and then dragging it to the end of the area you want to change. You can also use the arrow keys and hold shift, but this takes longer typically.

5 0
3 years ago
A personal phone directory contains room for first names and phone numbers for 30 people. Assign names and phone numbers for the
Fynjy0 [20]

Answer:

# include <iostream.h>

# include <stdio.h>

# include <string.h>

using namespace std;

class citizen

{      

    int i;

    public string name[30];

    public long int phonenumber[30];

    public void addindividual(string name1)

     {      

           If (i<=30)

            {     int flag=0;

                  for(int j=0; j<=i;j++)

                  {

                     if (strcmp(name[i], name1)

                      {

                          flag=1;

                      }

                     else

                     {  

                           flag=0;

                     }

                  }

                  If (flag)

                 {

                  if (i<30)

                  {

                  for(j=i+1;j<=30; j++)

                  {

                        cout<<"Enter the name:"; getchar(name[j]);

                        cout<<"Enter the phone number:"; cin>>phonenumber[j];

                         i++;

                   }

                  else  

                   {

                        cout<<"The person already exists";

                        exit();

                   }

              }

            else

             {

                 cout<<"array is full:";

                 exit();

             }

     }

}

Void main()

{

     string str;

    cout<<" Enter name:";

    getline(cin, str); ;

     citizen c1=new citizen();

     c1.addindividual(name1);

}

Explanation:

With a little more effort you can make the program allow the user to enter any number of details, but less than 30 overall. We have used here flag, and as a programmer we know why we use the Flag. It is used to check whether certain Boolean condition is fulfilled or not. Here, we are checking whether a given name is present in the array of names, and if it is not present, we add that to the list. And if the name is present, we print, it already exist.

4 0
3 years ago
State whether True / False:<br>The pause option stops the recording temporarily.*<br>True<br>False​
defon

Answer:

true

Explanation:

when you pause a recording it will temporarily stop but, when you hit record again it will continue where you left off

7 0
3 years ago
You are using a polynomial time 2-approximation algorithm to find a tour t for the metric traveling salesman problem. Which of t
Svet_ta [14]

Answer:

B. The cost of tour t is at most twice the cost of the optimal tour.

Explanation:

You are using a polynomial time 2-approximation algorithm to find a tour t for the traveling salesman problem.

The cost of tour t is at most twice the cost of the optimal tour

The equation represented as Cost(t) <= 2 Cost(T)

Where

Cost (t) represents cost of tour t

Cost(T) represents cost of the optimal tour

3 0
3 years ago
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