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LekaFEV [45]
3 years ago
11

|| Area of a regular polygon

Mathematics
1 answer:
ELEN [110]3 years ago
5 0

Answer:

The area of any regular polygon is given by the formula: Area = (a x p)/2, where a is the length of the apothem and p is the perimeter of the polygon. Plug the values of a and p in the formula and get the area. As an example, let's use a hexagon (6 sides) with a side (s) length of 10.

Step-by-step explanation:

idk if you added a picture but

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Can someone help me with this math homework please!
Misha Larkins [42]

Answer:

Step-by-step explanation:

In step one she has added 1x to each side of the statement

in step two she has taken five away from both sides of the equation therefore simplifying the entire equation

in step three she divided both sides by three to have the unknown value on one side of the equation

6 0
3 years ago
Please help !!
Rama09 [41]
Just add the two given angles together.
6 0
3 years ago
Read 2 more answers
HELP PLEASE IM BEING TIMED!! WILL GIVE BRAINLIEST!!
kolbaska11 [484]

ANSWER

The correct choice is C.

EXPLANATION

The perimeter of a rectangle is given by;

P=2(w+l)

For the first rectangle, the perimeter is;

P=2(8+4)=24

For the second rectangle, the perimeter is

P=2(8+8)=32

For the third rectangle, the perimeter is

P=2(8+12)=40

The correct choice is C

8 0
3 years ago
2. Describe how to use the conjugate to divide 2 − i by 3 + 2i, and then find the quotient.
DaniilM [7]

Answer:

\frac{4}{13}-\frac{7}{13}i

Step-by-step explanation:

\frac{2-i}{3+2i}

Multiply and divide by the conjugate.

The conjugate is the denominator with the sign of the complex number the opposite of the denominator.

\frac{2-i}{3+2i}\frac{3-2i}{3-2i}\\ =\frac{2\times (3-2i)-i\times (3-2i)}{3^2-(2i)^2}\\ =\frac{6-4i-3i+2i^2}{9+4}\\ =\frac{4-7i}{13}\\ =\frac{4}{13}-\frac{7}{13}i

Quotient = \frac{4}{13}-\frac{7}{13}i

7 0
3 years ago
Solve the following equation algebraically:
Gre4nikov [31]

Answer:

\boxed{\sf \ \ \ answer \ b. \ \ +5 \ \ \ }

Step-by-step explanation:

Hello

let's assume that we are looking for x >=0

4x^2=100  \dfrac{4x^2}{4}=x^2=\dfrac{100}{4}=25\\\sqrt{x^2}=25\\ |x| = 5  x = 5 \ or \ x=-5

Let's assume that we are looking for x>=0

so the correct answer is 5

8 0
3 years ago
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