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3 years ago

Simplify the expression with using scientific notation (4 times 10 8)2

Mathematics

1 answer:

kifflom [539]3 years ago

8 0

The scientific notation:

$a\cdot10^n\\\\1\leq a < 10;\ n\in\mathbb{Z}$

$(4\cdot10^8)^2=4^2(10^8)^2=16\cdot10^{8\cdot2}=16\cdot10^{16}\\\\=1.6\cdot10\cdot10^{16}=1.6\cdot10^{17}$

Used:

$(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}\\\\a^n\cdot a=a^{n+1}$

Answer: (4 × 10⁸)² = 1.6 × 10¹⁷

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3 years ago

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Jlenok [28]

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4 years ago

Solve the equations. a. (x − 2)^2 = 9 b. 3(x − 2)^2 = 9 c. 6 = 24(x + 1)^2

seropon [69]

Answer: a) x = 5 or -1 b) x = √3+2

c) x = -1/2 or -3/2

Step-by-step explanation:

a) (x − 2)² = 9

First step is to take the square root of both sides to eliminate the square

√ (x − 2)² = √9

x-2 = +-3

x = +3+2

x = 5 and;

x = -3+2

x = -1

x = 5 or -1

b) 3(x-2)² = 9

First we divide both sides by 3 to get;

(x-2)² = 9/3

(x-2)² = 3

Second step is to take the square root of both sides to eliminate the square

√(x-2)² = √3

x-2 = √3

x = √3+2

c) 6 = 24(x+1)²

Dividing both sides by 24, we have

6/24 = (x+1)²

1/4 = (x+1)²

Taking the square root of both sides we have

√1/4 = √(x+1)²

= +-1/2 = x+1

x = +1/2-1 = -1/2 and;

x = -1/2-1 = -3/2

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3 years ago

What is the measure of ∠HFG? (See attachment)

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3 years ago

Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different

N76 [4]

Answer:

(a) As time increases, the amount of water in the pool increases.

11 gallons per minute

(b) 65 gallons

Step-by-step explanation:

From inspection of the table, we can see that as time increases, the amount of water in the pool increases.

We are told that Ann adds water at a constant rate. Therefore, this can be modeled as a linear function.

The rate at which the water is increasing is the rate of change (which is also the slope of a linear function).

Choose 2 ordered pairs from the table:

$\textsf{let}\:(x_1,y_1)=(8, 153)$

$\textsf{let}\:(x_2,y_2)=(12,197)$

Input these into the slope formula:

$\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11$

Therefore, the rate at which the water in the pool is increasing is:

11 gallons per minute

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

$y-y_1=m(x-x_1)$