Melinda is saving at the rate of 60/5 = $12 per week
Marcus is saving $14 per week
Difference is $2
Melinda is savinf $2 less than marcus each week
Answer:
Lower limit: 113.28
Upper limit: 126.72
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Middle 60%
So it goes from X when Z has a pvalue of 0.5 - 0.6/2 = 0.2 to X when Z has a pvalue of 0.5 + 0.6/2 = 0.8
Lower limit
X when Z has a pvalue of 0.20. So X when 
Upper limit
X when Z has a pvalue of 0.80. So X when 
A = 180(n - 2)
a = 180n - 180*2
a = 180n - 360
180n - 360 = a
180n = a + 360
n = (a + 360) / 180
Numerator for fraction above = ( a + 360), denominator = 180
The cost of 0.5 kg of bananas is 393.60 Colones as per the given conversion rates
Conversion rate of 1 USD to Costa Rican Colones = 518 Colones
The conversion rate of kg to pounds given in the question: 1 kg = 2.2025 lbs
Cost of one pound of bananas = $0.69
Bananas required to be purchased = 0.5kg
Converting 0.5kg bananas to pounds = 0.5*2.2025 = 1.10125 pounds
Cost of 1.10125 pound of bananas in dollars = 1.10125*0.69 = 0.7598
Cost of 1.1025 pounds of bananas in Colones = 0.7598*518 = 393.60 Colones
Hence, the cost is 393.60
Therefore, the cost of 0.5 kg bananas in Colones is 393.60 Colones
Learn more about conversion rate:
brainly.com/question/2274822
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