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san4es73 [151]
3 years ago
8

When a slice of buttered toast is accidentally pushed over the edge of a counter, it rotates as it falls. If the distance to the

floor is 55 cm and for rotation less than 1 rev, what are the (a) smallest and (b) largest angular speeds that cause the toast to hit and then topple to be butter-side down

Physics
1 answer:
aniked [119]3 years ago
6 0

Answer:

a) = 4.69rad/s

b) = 14.01rad/s

Explanation:

see attached file

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Answer:

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Explanation:

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How is amplitude related to volume?
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Finally, the amount of increased volume<span> that is achieved by an increase in </span>amplitude<span>is also affected by the frequency. So, turning the </span>amplitude<span> level in the mid-range sound from the previous example will not have the same proportional effect on loudness as the bass sound.</span>
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Read 2 more answers
You are designing a new piece of fishing equipment that will allow you to catch a fish from the surface. You know that water ref
OleMash [197]

Answer:

Law of refraction

Explanation:

An experiment to analyze the refraction of light in water can easily be performed with a laser pointer and protractor.

We throw the fishing rod line into the water, place the protractor at the point where the line touches the water and use the direction of the line for the direction of the laser pointer (on), the laser is visible by the reflection on the particles in the air.

The vertical line is called Normal and all angles must be measured with respect to this reference in optics.

Having these angles and the refractive index of water we can use the law of refraction

         n₁ sin θ₁  = n₂ sin θ₂

         θ₂ = sin^{-1} ( \frac{n_1}{n_2} \ sin \ \theta_1 )

we can repeat several times to analyze several different input points (different angles) and to decrease the errors in the measurements.

the refractive index of air is n1 = 1 and n2= 1.33  (water)

4 0
3 years ago
In order to be considered scientific, evidence must be:
zhenek [66]
Reviewed by many sources. for example, it must be reviewed by scientist too
7 0
4 years ago
A 1.2 kg block is held at rest against the spring with a force constant k= 730 N/m. Initially, the spring is compressed a distan
Nesterboy [21]

Answer:

Compression distance: d \approx 0.102\,m

Explanation:

According to this statement, we know that system is non-conservative due to the rough patch. By Principle of Energy Conservation and Work-Energy Theorem, we have the following expression that represents the system having a translational kinetic energy (K), in joules, at the expense of elastic potential energy (U), in joules, and overcoming work losses due to friction (W_{l}), in joules:

K + W_{l} = U (1)

By definitions of translational kinetic and elastic potential energies and work losses due to friction, we expand the equation described above:

\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2}  \cdot k \cdot d^{2} (2)

Where:

m - Mass of the block, in kilograms.

v - Final velocity of the block, in meters per second.

\mu - KInetic coefficient of friction, no unit.

g - Gravitational acceleration, in meters per square second.

s - Width of the rough patch, in meters.

k - Spring constant, in newtons per meter.

d - Compression distance, in meters.

If we know that m = 1.2\,kg, v = 2.3\,\frac{m}{s}, \mu = 0.44, g = 9.807\,\frac{m}{s^{2}}, s = 0.05\,m and k = 730\,\frac{N}{m}, then the compression distance of the spring is:

\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2}  \cdot k \cdot d^{2}

m\cdot v^{2} + 2\cdot m\cdot g \cdot s = k\cdot d^{2}

d = \sqrt{\frac{m\cdot (v^{2}+2\cdot g\cdot s)}{k} }

d \approx 0.102\,m

4 0
3 years ago
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