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bezimeni [28]
3 years ago
11

How do you solve this problem

Mathematics
2 answers:
Bingel [31]3 years ago
6 0
As, it is a right angled triangle
Taking, 
tan 60 = x/9 [Perpendicular/Base]
∴ √3 = x/9
x=9√3
or x= 9*1.732
∴ x= 15.588
NNADVOKAT [17]3 years ago
4 0
Answer is 9 root3
this is because it is one of the special triangle: with special ration of 2x:root3x:1x
you could plug values into the sin formula as well.

9 cm is the smallest length since it is across from the 30° angle. so there fore 9 is 1x
x is 9.

root3x = 9root3
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Could you build a triangle from each of the 3 lengths?
lianna [129]
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5, 5, 3 forms a triangle (isosceles)
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7, 8, 15 technically forms a triangle with an area of zero units. The vertices would be co-linear.
This will often be ignored as it has little practical use.

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7 0
2 years ago
What is a regular Polygon? Name all the types of polygon.(HELP ASAP)
Damm [24]

Answer:

A regular polygon is a polygon with sides of equal length. Some examples include, a equilateral triangle, square, regular pentagon, regular hexagon, regular heptagon, regular octagon, regular nonagon, regular decagon...

7 0
2 years ago
P = a^b + b^a. Given a,b,p are prime numbers. find the value of p
VARVARA [1.3K]
2³   +  3² = 2*2*2+3*3= 8+9=17
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4 0
2 years ago
8+a=21 plssssssssssssszzzz​
attashe74 [19]

Answer:

13

Step-by-step explanation:

because a is the missing number. Well, 21 minus or -  8 is equal to 13.

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B8%7D%2B%5Csqrt%7B18%7D-%5Csqrt%7B32%7D" id="TexFormula1" title="\sqrt{8}+\sqrt{18}-\
eduard

√8+√18−√32
√2^2·2+√3^2·2−√2^4·2
√2^ 2·√2+√3^2·√2−√2^4·√2


√2 is the answer
7 0
3 years ago
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