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Oksanka [162]
4 years ago
14

What is the independent variable of an equation?

Mathematics
1 answer:
bulgar [2K]4 years ago
8 0
The independent variable of an equation is x, or something u can change. in linear equations, for example, it is y=3x+4. and  x is the independent variable cause most of the time u will plug in or substitute a number for x. 
You might be interested in
The length of the second side of a triangle is 2 inches less than the length of the first side.The length of the third side is 1
Luda [366]

Answer:

The lenght of the tree sides of the triangle are:

first side: 21 inches

second side: 19 inches

third side: 33 inches

Step-by-step explanation:

a + b + c = 73

b = a - 2

c = a + 12

a = leght of the first side of the triangle

b = lenght of the second side of the triangle

c = lenght of the third side of the triangle

then:

a + (a-2) + (a+12) = 73

3a - 2 + 12 = 73

3a + 10 = 73

3a = 73 - 10

3a = 63

a = 63/3

a = 21 inches

b = a - 2

b = 21 - 2

b = 19 inches

c = a + 12

c = 21 + 12

c = 33 inches

Check:

21 + 19 + 33 = 73

related task:

https://brainly.lat/tarea/1029254

6 0
3 years ago
Abigail is raising money for a school trip by selling bags of chips and packs of cookies. The price of each bag of chips is $1.5
Mkey [24]

The number of bags of chips sold is 8 and the number of packs of cookies sold is 12

<em><u>Solution:</u></em>

Let "a" be the number of bags of chips sold

Let "b" be the number of packs of cookies sold

Given that,

Cost of one bag of chips = $ 1.50

Cost of one pack of cookies = $ 1.25

Yesterday Abigail made $27 from selling a total of 20 bags of chips and packs of cookies

<em><u>So we can frame a equation as:</u></em>

Number of bags of chips sold + number of packs of cookies sold = 20

a + b = 20 ---- eqn 1

Also given that Abigail made $27 from selling

number of bags of chips sold x Cost of one bag of chips + number of packs of cookies sold x Cost of one pack of cookies = $ 27

a \times 1.50 + b \times 1.25 = 27

1.5a + 1.25b = 27 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "b"</u></em>

From eqn 1,

a = 20 - b ---- eqn 3

Substitute eqn 3 in eqn 2

1.5(20 - b) + 1.25b = 27

30 - 1.5b + 1.25b = 27

-0.25b = -3

<h3>b = 12</h3>

Therefore from eqn 3,

a = 20 - b = 20 - 12 = 8

<h3>a = 8</h3>

<em><u>Thus we have:</u></em>

number of bags of chips sold = 8

number of packs of cookies sold = 12

3 0
3 years ago
Please answer these with lots of detail. I want to be able to understand the topic and material well.
IRISSAK [1]

Step-by-step explanation:

Q3

(a) If 0 < |x − 1| < δ, then |f(x) − 2| < 2

What this means is, how far can x stray from the x=1 line such that f(x) stays within 2 units of the y=2 line (0 < f(x) < 4).

If we move 2 units left of x=1, we get f(x) = 4.

If we move about 3.5 units right of x=1, we get f(x) = 4.

Therefore, δ can't be more than 2.

(b) If 0 < |x| < δ, then |f(x) − 3| < 1

What this means is, how far can x stray from the x=0 line such that f(x) stays within 1 unit of the y=3 line (2 < f(x) < 4).

If we move 1 unit left of x=0, we get f(x) = 4.

If we move 1 unts right of x=0, we get f(x) = 2.

Therefore, δ can't be more than 1.

Since f(x) isn't continuous within this domain, we can't conclude that the limit exists.

Q4

(a) Yes.  If δ = 0.25, then 0.75 < x < 1.25, and f(x) > 200.

(b) No.  f(1) = 300, so even if δ = 0, f(x) will be less than 400.

(c) Yes.  If δ ≈ 0.1, then 0.9 < x < 1, and f(x) > 450.

6 0
4 years ago
HELP PLEASE!
Novosadov [1.4K]

Answer:

x = 25

Step-by-step explanation:

This is an equilateral triangle as all 3 angles are marked as equal.

Hence the 3 sides are equal

Equate any 2 and solve for x

4x - 30 = 3x - 5 ( subtract 3x from both sides )

x - 30 = - 5 ( add 30 to both sides )

x = 25

As a check on the sides

4x - 30 = (4 × 25) - 30 = 100 - 30 = 70

3x - 5 = (3 × 25 ) - 5 = 75 - 5 = 70

2x + 20 = (2 × 25 ) + 20 = 50 + 20 = 70

confirming that x = 25


6 0
3 years ago
Model the division on the grid 26÷2=(_÷2)+(_÷2)=_+_=_
fomenos
I think the answer is =3.25
6 0
4 years ago
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