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givi [52]
3 years ago
8

Solve for x.........................

Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0

Answer:

C

Step-by-step explanation:

To solve this equation we need to first get the standard form of a quadratic equation by bringing every term to one side of the equal to .

so

4x^{2} +2x^{2} -3x+2x-16+4=0

combining the like terms in the equation we get

6x^{2} -x-12=0

you can use the factoring to simplify it

so the given equation can be written as

6x^{2} -9x+8x-12=0

using the grouping to factor we get

3x(2x-3) +4(2x-3)=0

(3x+4)(2x-3)=0

using the zero root property now

3x+4=0

2x-3 =0

so that gives us two values

x=\frac{-4}{3}

and

x=\frac{3}{2}

option : C

marin [14]3 years ago
7 0
Sorry I don’t know how to type it

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Please answer ASAP!!! :)<br> .-. .-. .-. .-. .-. .-.
SSSSS [86.1K]

Answer:

I highly recommend that it must be the second story

5 0
3 years ago
Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b
jeka94

Answer:

Step-by-step explanation:

From the given information; Let's assume that  R should represent the set of all possible outcomes generated from  a bit string of length 10 .

So; as each place is fitted with either 0 or 1

\mathbf{|R|= 2^{10}}

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if  a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

\mathbf{P(E) = \dfrac{|E|}{|R|}}

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:

\mathbf{{|E|}=1 }   ; \mathbf{|R|= 2^{10}}

\mathbf{P(E) = \dfrac{1}{2^{10}}}

4 0
3 years ago
Order these numbers from least to greatest.
PSYCHO15rus [73]
<h3>Answer:  3.1691, 5.8, 5.802, 5.82</h3>

Explanation:

The smallest item is 3.1691 which is listed first. This is because 3 is smaller than 5.

Now to sort the values that start with 5.

Think of 5.82 as 5.820; think of 5.8 as 5.800

We can see that 820 is larger than 800, which means 5.820 is larger than 5.800; in short, 5.82 > 5.8

Through similar logic, we can see that 5.82 > 5.802 and it further means 5.82 is the largest item. The next largest is 5.802

The sub-list {5.802, 5.82, 5.8} sorts to {5.8, 5.802, 5.82}. These values are then written after the 3.1691 mentioned. This will produce the fully sorted list from smallest to largest.

4 0
3 years ago
4) Which set contains NO Irrational Nurabers?
xz_007 [3.2K]

Answer:

d

Step-by-step explanation:

d does not have any repeaing decimals, or any other type of irrational number

7 0
3 years ago
How would you differentiate this problem?
DochEvi [55]

Answer:

hope this helps you in some way

7 0
3 years ago
Read 2 more answers
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