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2 years ago

4) Which set contains NO Irrational Nurabers?

Mathematics

1 answer:

xz_007 [3.2K]2 years ago

7 0

Answer:

Step-by-step explanation:

d does not have any repeaing decimals, or any other type of irrational number

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Find the value of y and z.

My name is Ann [436]

Answer:

z= 125 because they are congruent and y = 55 because they are congruent

I hope this is good enough:

3 0

3 years ago

Triangle LMN is plotted on a coordinate plane. It is then dilated by a factor of 2 using the origin as the center of dilation, a

Fynjy0 [20]

Answer:

B. ( x , y )→(2 x - 5, 2 y + 3)

Step-by-step explanation:

when x goes to the left it is negative and when y goes up it is positive, making B the only possible answer choice.

8 0

3 years ago

Please help me with circle questions below

IRINA_888 [86]

For first question, What is approximate value of "......" this part is missing so please write whose approximate value question is asking to find

For second question we have to find $tan\Theta$

In right triangle ABC as show in attachment,

$tan\Theta = \frac{opposite side}{adjacent side} = \frac{AB}{BC}$ ----(1)

Now AB is given by distance of point A from x axis which will be given by its y - coordinate. So $AB = \frac{1}{2}$

Similarly BC is the distance of point A from y axis (horizontal distance ) and that will be given by x coordinate of A. So $BC = \frac{\sqrt{3}}{2}$

Plug these values in equation (1)

$tan\Theta = \frac{AB}{BC} = \frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}$

To divide fractions we flip (reciprocal ) bottom fraction and multiply it to top fraction as shown

$tan\Theta = \frac{1}{2} \times \frac{2}{\sqrt{3}}$

Now 2 in top and bottom cancels out so we are left with

$tan\Theta = \frac{1}{\sqrt{3}}$

so thats the final answer for $tan\Theta$

8 0

3 years ago

Find the 10 degree value can u help me on it

dem82 [27]

Solution:-10

As <AGQ and <EQG are corresponding interior angles

$\\ \qquad\quad\sf{:}\twoheadrightarrow 60°+a=180$

$\\ \qquad\quad\sf{:}\twoheadrightarrow a=180-60$

$\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow a=120}$

<AGQ=<PQR=60°
<BHF=<PRQ=75°

$\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow b=75°}$

According to angle sum property

$\\ \qquad\quad\sf{:}\twoheadrightarrow b+c+$

$\\ \qquad\quad\sf{:}\twoheadrightarrow c+75+60=180$

$\\ \qquad\quad\sf{:}\twoheadrightarrow c+135=180$

$\\ \qquad\quad\sf{:}\twoheadrightarrow c=180-135$

$\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow c=45°}$

7 0

2 years ago

Can you help me estimate this

Assoli18 [71]

the answer would be $110.00

mark brailiest

5 0

2 years ago

Read 2 more answers