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Andrej [43]
2 years ago
9

4) Which set contains NO Irrational Nurabers?

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
7 0

Answer:

d

Step-by-step explanation:

d does not have any repeaing decimals, or any other type of irrational number

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A sphere with center A is shown. Which represents a radius?
Lunna [17]
A because radius is half of the diameter
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2 years ago
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The sum of two consecutive integers is 85. What are those two<br> integers?
chubhunter [2.5K]

Answer:

41 and 42

Step-by-step explanation:

Let the integers be x and x + 1

=> x + x + 1 = 85

=> 2x + 1 = 85

=> 2x = 84

=> x = 84/2

=> x = 41

Integers are :

41 and 42

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2 years ago
A two-dimensional figure with four sides has 2 pairs of opposite parallel sides, 4 congruent sides, and 4 right angles.
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Parallelogram rectangle square rhombus
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3 years ago
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5/8-11/20=?<br><br> Help what’s the answer I’m stuck on finding the LCM of the denominators
zhannawk [14.2K]

Answer:

3/40

Step-by-step explanation:

  • \frac{5}{8} - \frac{11}{20}
  • \frac{25}{40} - \frac{22}{40} (LCM is 40)
  • \frac{25-22}{40}
  • \frac{3}{40}

Therefore, the answer is 3/40!

4 0
2 years ago
A) how many ways are there to choose 10 players to take the field?
Kruka [31]

A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.

B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4. (13−10)! 3!

C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =

10! 3!

9!1! 1!2! 10! 3!

8!2! 2!1! 10! 3!

7!3! 3!0!

= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =

= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =

= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285 1·2·3

<span>possible choices.</span><span> 
</span>

  


5 0
3 years ago
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