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3 years ago

¿Que es un átomo???????

1 answer:

5 0

Un átomo es una porción material menor de un elemento químico que interviene en las reacciones químicas y posee las propiedades características de dicho elemento.

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An elevator is accelerating upward at a rate of 3.6 m/s2. a block of mass 24 kg hangs by a low-mass rope from the ceiling, and a

kozerog [31]

The answer:

When the elevator accelerates upward at a rate of 3.6 m/s², the value of the acceleration becomes

A=g+3.6=13.4 m/s²
and by using the newton's law, F=mass x A, we have
T1= (24 + 90 )x 13.4= 1527.6 N, where T1 is the Tension in upper rope
 and
T2= ( 90 )x 13.4= 1206N, where T2 is the Tension in lower rope

When the elevator accelerates downward at a rate of 3.6 m/s², the value of the acceleration becomes
A=9.8 - 3.6 = 6.2 m/s²

T1= (24 + 90 )x 6.2= 706.8 N, where T1 is the Tension in upper rope
and
T2= ( 90 )x 6.2= 558N, where T2 is the Tension in lower rope

5 0

2 years ago

How much does a 44 kg child weigh on Earth?

Akimi4 [234]

Well if the child weighs 44 kg then 44 kg. Do you mean if they weigh 44 kg in space to earth?

4 0

3 years ago

Read 2 more answers

Acceleration is a vector quantity. O O A. True B. False

PtichkaEL [24]

True ( I think ) ............................

3 0

3 years ago

Read 2 more answers

Represent 7468 N with SI units having an appropriate prefix. Express your answer to four significant figures and include the app

sergeinik [125]

Answer:

7.468 kN

Explanation:

Here the force of 7468 Newton is given.

Some of the prefixes of the SI units are

kilo = 10³

Mega = 10⁶

Giga = 10⁹

The number is 7468.0

Here, the only solution where the number of significant figures is kilo

1 kilonewton = 1000 Newton

$1\ Newton=\frac{1}{1000}\ kilonewton$

$\\\Rightarrow 7468\ Newton=\frac{7468}{1000}\ kilonewton\\ =7.468\ kilonewton$

So 7468 N = 7.468 kN

3 0

2 years ago

The internuclear distance between two closest Ar atoms in solid argon is about 3.8 A. The polarizability of argon is 1.66e-30 m3

oee [108]

Answer:

83.72 K

Explanation:

$\alpha$ = Polarizability of argon = $1.66\times 10^{-30}\ m^3$

I = First ionization = 1521 kJ/mol

r = Distance between atoms = 3.8 A

R = Gas constant = 8.314 J/mol K

T = Boiling point

Potential energy due to dispersion of gas is given by

$P=-\frac{3}{4}\frac{\alpha^2I}{r^6}\\\Rightarrow P=-\frac{3}{4}\frac{(1.66\times 10^{-30})^2\times 1521\times 10^3}{(3.8\times 10^{-10})^6}\\\Rightarrow P=-1044.01\ J/mol$

Kinetic energy is given by

$K=\frac{3}{2}RT$

The potential and kinetic energy will balance each other

$P=\frac{3}{2}RT\\\Rightarrow 1.04401\times 10^{-33}=\frac{3}{2}RT\\\Rightarrow T=\frac{1044.01\times 2}{3\times 8.314}\\\Rightarrow T=83.72\ K$

The boiling point of argon is 83.72 K

7 0

3 years ago