An AC source is connected to a series combination of a light bulb and a variable capacitor. If the capacitance is increased, the
1 answer:
Answer:
Increases
Explanation:
Since power P=IV
Then it means when current increases, the power increases hence brightness increases. I represent current, P is power and v is voltage.
Current of capacitor when in series connection is given by
where I is current across capacitor, f is frequency, C is capacitance and v is voltage across capacitance. From this second formula, it is evident that an increase in capacitance increases the current across the capacitor. Therefore, if current increases, power also increases leading to an increase in brightness
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Recall this kinematic equation:
a =
This equation gives the acceleration of the object assuming it IS constant (the velocity changes at a uniform rate).
a is the acceleration.
Vi is the initial velocity.
Vf is the final velocity.
Δt is the amount of elapsed time.
Given values:
Vi = 0 m/s (the car starts at rest).
Vf = 25 m/s.
Δt = 10 s
Substitute the terms in the equation with the given values and solve for a:
a =