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Anastaziya [24]
3 years ago
6

A coconut fell from a tree. it fell a distance of 38m. how long was the coconut falling?

Physics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

2.8 seconds

Explanation:

Given:

Δy = 38 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(38 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 2.8 s

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A boat radioed a distress call to a Coast Guard station. At the time of the call, a vector A from the station to the boat had a
VashaNatasha [74]

Answer:

d = 39.7 km

Explanation:

initial position of the boat is 45 km away at an angle of 15 degree East of North

so we will have

r_1 = 45 sin15 \hat i + 45 cos15 \hat j

r_1 = 11.64 \hat i + 43.46\hat j

after some time the final position of the boat is found at 30 km at 15 Degree North of East

so we have

r_2 = 30 cos15\hat i + 30 sin15 \hat j

r_2 = 28.98\hat i + 7.76 \hat j

now the displacement of the boat is given as

d = r_2 - r_1

d = (28.98\hat i + 7.76 \hat j) - (11.64 \hat i + 43.46\hat j)

d = 17.34 \hat i - 35.7 \hat j

so the magnitude is given as

d = \sqrt{17.34^2 + 35.7^2}

d = 39.7 km

4 0
3 years ago
Por favor ayuda que ejercicio debo hacer para enflacar en una semana xd
Serggg [28]

Answer:

Un excelente ejercicio para perder barriga rápidamente es correr, ya que el cuerpo gasta una mayor cantidad de calorías en un corto período de tiempo, en tan sólo 30 minutos corriendo se queman unas 300 calorías.

...

Qué ejercicios realizar

Correr. ...

Clase aeróbica. ...

Saltar cuerda. ...

Bicicleta. ...

Caminar rápido. ...

Natación.

Explanation:

dame coronita por favor

8 0
3 years ago
How did William Harvey's ideas about autopsies differ from the cultural ideas of his time?
rusak2 [61]
William Harvey wanted to conduct public autopsies si that the general public might learn from them. However, at that time, anatomical studies were considered as taboos and were disproved by the doctrines. Leonardo da Vinci's anatomical drawings were also charged with heresy. 
8 0
3 years ago
A stack of paper contains 500 sheets of paper. The stack has dimensions of 0.297 m x 21.0 cm x 50.0 mm.
Art [367]

Answer:

0.1 mm

Explanation:

Given data :  A stack of paper contains 500 sheets of paper.

The stack has dimensions of 0.297 m x 21.0 cm x

50.0 mm.

To Find : What is the thickness of one sheet of paper

So,

1 m = 1000 mm

1 m = 100 cm

1 cm =  10 mm

The stack has dimensions of 0.297 m x 21.0 cm x 50.0 mm.

0.297 m = 297 mm

21 cm = 210 m

297 mm * 210 mm are paper length width

Hence 50 mm is thickness of 500 sheets

-  thickness of one sheet of paper = 50/500  = 1/10 mm

= 0.1 mm

Hope It Helps :)

4 0
3 years ago
Before a collision, a 50.0-kg object is moving at +5.0 m/s. Find the impulse that acted on the object if, after the collision, i
Virty [35]

Answer:

<em>J=600 kg m/s </em>

Explanation:

<u>Impulse And Momentum </u>

Suppose a particle is moving at a certain speed v_1 and changes it to v_2. The impulse J is equivalent to the change of linear momentum. The momentum can be computed by

p=mv

The initial and final momentums are given, respectively, by:

p_1=mv_1,\ p_2=mv_2

Thus, the change of momentum is

\Delta p=p_2-p_1=m(v_2-v_1)

It's equal to the Impulse J

J=\Delta p

J=m(v_2-v_1)

Our data is

m=50\ kg,\ v_1=5\ m/s,\ v_2=17\ m/s

J=50\ (17-5)

J=600\ kg\ m/s

7 0
3 years ago
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