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mr Goodwill [35]
3 years ago
15

Help Plz :) Explain the answer if you can

Physics
1 answer:
Lyrx [107]3 years ago
7 0
Group 1, 2, and 3 are
A. Metals

Group 1: Alkali Metals
Group 2: Alkali Earth Metals
Group 3: Transition Metals
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How much carbon dioxide (co2) does natural gas emit compared with other fossil fuel
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3 years ago
Number of vibrations (waves) in an amount of time
m_a_m_a [10]

Answer:

I think frequency not sure though

How frequently a wave or vibration occurs during a span of time, determines the waves frequency. Frequency is the number of waves per unit time. The unit for frequency if a Hertz ( 1/second). The speed a wave travels is the wavelength multiplied by this frequency. The amplitude of a wave is the maximum distance the wave is displaced.

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2 years ago
When two objects of different masses, different temperatures, and different sizes are placed in thermal contact, energy will alw
denpristay [2]

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a) from the hotter object to the cooler object

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temperature moves by conduction,  which is associated with the movement of  atoms or molecules and the always move from hight temperatures to lower temperatures to attain thermal equilinrium of the system.

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6 0
3 years ago
Vector A⃗ points in the negative y direction and has a magnitude of 5 km. Vector B⃗ has a magnitude of 15 km and points in the p
Harlamova29_29 [7]
C
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7 0
3 years ago
What is the gravitational force between Mars and the sun? 7.43 × 1030 N 1.79 × 1026 N 1.65 × 1021 N 3.76 × 1032 N
VMariaS [17]

The gravitational force between Mars and the Sun is 1.65\cdot 10^{21} N

Explanation:

The magnitude of the gravitational force between two objects is given by  the equation:

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

In this problem, we have:

m_1 = 1.99\cdot 10^{30} kg is the mass of the Sun

m_2 = 6.39\cdot 10^{23} kg is the mass of Mars

r=229\cdot 10^6 km = 229\cdot 10^9 m is the average distance Mars-Sun

Substituting into the equation, we find the gravitational force:

F=(6.67\cdot 10^{-11})\frac{(1.99\cdot 10^{30})(6.39\cdot 10^{23})}{(229\cdot 10^9)^2}=1.62\cdot 10^{21} N

So, the closest answer is

1.65\cdot 10^{21} N

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

4 0
3 years ago
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