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mr Goodwill [35]

3 years ago

15

Help Plz :) Explain the answer if you can

1 answer:

Lyrx [107]3 years ago

7 0

Group 1, 2, and 3 are
A. Metals

Group 1: Alkali Metals
Group 2: Alkali Earth Metals
Group 3: Transition Metals

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Will someone please help? ASAP- it’s an easy 25 points!!

Artyom0805 [142]

Answer:

The missing force is 110 newtons

Explanation:

A net force of 25 newtons means the larger amount of force (135 newtons) has 25 fewer newtons. To get the missing force you subtract 135 from 25, giving you 110 newtons.

6 0

3 years ago

What is is the goal of both physical and behavioral adaptions ?

Ad libitum [116K]

It’s A .
- correct me if i’m wrong -

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3 years ago

Read 2 more answers

Atomic theory that states that atoms have three fundamental parts, and that electrons orbit the nucleus:

zhannawk [14.2K]

The <span>Atomic theory that states that atoms have three fundamental parts, and that electrons orbit the nucleus is the kinetic molecular theory of gases.</span>

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3 years ago

A 56 kg boat that is 7.6 m in length is initially 7.6 m from the pier. A 39 kg child stands at the end of the boat closest to th

svlad2 [7]

Answer:

Explanation:

Given

mass of boat $M=56\ kg$

mass of Person $m=39\ kg$

Length of boat $L=7.6\ m$

Center of mass of boat and child

$x_{cm}=\frac{M\times 0.5L+m\times L}{M+m}$

$x_{cm}=\frac{56\times 0.5\times 7.6+39\times 7.6}{56+39}$

$x_{cm}=\frac{509.2}{95}$

$x_{cm}=5.36---1$

when child reaches another end of boat, boat is shifted by x cm

Center of mass of the system will remain the same

$x'_{cm}=\frac{M\times (x+0.5L)+m\times x}{M+m}$

$x'_{cm}=\frac{56\times (x+0.5\times 7.6)+39\times x}{56+39}----2$

Equating 1 and 2 we get

$509.2=95x+212.8$

$x=3.12\ m$

6 0

4 years ago

An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s1045 rad/s ). If a particular disk is s

kumpel [21]

To solve this problem we must keep in mind the concepts related to angular kinematic equations. For which the angular velocity is defined as

$\omega_f =\omega_i-\alpha t$

Where

$\omega_f =$ Final angular velocity

$\omega_i =$ Initial angular velocity

$\alpha =$ Angular acceleration

t= time

In this case we do not have a final angular velocity, then

$\omega_i = \alpha t$

Re-arrange for $\alpha$

$\alpha= \frac{\omega_i}{t}$

$\alpha = \frac{910}{0.167}$

$\alpha = 5449.1 rad\s^2$

Therefore the mangitude of the angular aceleration is 5449.1rad/s²

6 0

4 years ago