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Fudgin [204]
4 years ago
11

what are the wavelengths of the two photons produced when a proton and antiproton at rest annhiilate (in meters)

Physics
1 answer:
Serjik [45]4 years ago
7 0

Answer:

Explanation:

mass of a proton = mass of an antiproton = 1.00727647 amu

total mass of proton and antiproton = 2.01455294 amu

1 amu = 931.5 x 10⁶ eV

2.01455294 amu = 1876.556064 x 10⁶ eV

Wavelength of radiation equivalent to this energy

=12375/1876.556064 x 10⁶ A = 6.5945 X 10⁻⁶A = 6.5945 X 10⁻¹⁶ m.

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A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from t
s344n2d4d5 [400]

Answer:

309 m

Explanation:

time apart = 0.8 s

speed of sound in air = 343 m/s

speed of sound in concrete = 3000 m/s

lets assume it time it takes to travel trough concrete = T

the time it takes to travel through air = T + 0.8 since they are 0.8 s apart

the distance traveled by both waves is the same, so we can equate the distance for both waves

distance  = speed x time

  • for concrete, distance = 3000 x T
  • for air, distance = 343 x (T + 0.8)

now equating the two distance together we have

3000 x T  = 343 x (T + 0.8)

3000T = 343T + 274.4

3000T - 343T = 274.4

T = 0.103 s

recall that distance = 3000 x T = 3000 x 0.103 = 309 m

5 0
3 years ago
A 0.5kg ball of clay originally moving at 6 m/s strikes a wall and comes to rest in 0.25s, what is the magnitude of the impulse
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Answer:

C I did USA testprep

Explanation:

5 0
3 years ago
Which energy transformation occurs when you light a gas burner?​
Eddi Din [679]

Answer:

Chemical energy to thermal(heat) energy

Explanation:

A gas burner contains chemical hydrocarbon such as methane, this methane is highly flammable.

The gas burner which contains methane when lighted up converts the chemical energy in the chemical to heat energy through the fire it produces. The fire then helps in heating up the surface it is applied to.

3 0
3 years ago
Can you see the equator from outer space??
DaniilM [7]
No, you can't see the equator.
4 0
3 years ago
The two lenses in a microscope are separated by 19.5 cm, and the focal length of the eyepiece lens is 2.75 cm.
Naya [18.7K]

Answer:

Explanation:

a )  If the image of this object is viewed with the eyepiece adjusted for minimum eyestrain (image at the far point of the eye) , the image from object lens must have been formed at the focus of eye lens . So the objective image must have been formed at 19.5 - 2.75 = 16.75 cm from the object lens.

b ) Let the object distance be u

For object lens

v = 16.75 cm , f = .35 cm

1/v - 1/u = 1/f

1/16.75  - 1/u = 1/ .35

.0597 - 1/u = 2.857

1/u = - 2.7973

u = .3575 cm

c ) Angular magnification

= \frac{v_o}{u_o} \times\frac{D}{f_e}

v₀ and u₀ are image and object distance for object lens , D = 25 cm and f_e is focal length of eye lens

= (16.75 / .3575) x( 25 / 2.75)

= 46.85 x 9.09

= 426

7 0
3 years ago
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