Answer:
linear density of the string = 4.46 × 10⁻⁴ kg/m
Explanation:
given,
mass of the string = 31.2 g
length of string = 0.7 m
linear density of the string = 
linear density of the string = 
linear density of the string = 44.57 × 10⁻³ kg/m
linear density of the string = 4.46 × 10⁻⁴ kg/m
Answer:
u = 10.63 m/s
h = 1.10 m
Explanation:
For Take-off speed ..
by using the standard range equation we have
R = 9.1 m
θ = 26º,
Initial velocity = u
solving for u
u = 10.63 m/s
for Max height
using the standard h(max) equation ..
h = 1.10 m
The correct answer is definitely C.
There are less than 16 valence electrons in 2 chlorine atoms, but they form a stable bond because a covalent bond should involve <span>a pair of electrons between atoms in a molecule. I thing it's pretty clear. Regards!</span>
Answer:
A.) 3605.6 N
B.) 33.7 degree
Explanation:
To find the result force acting on the wing of the airplane, we need to resolve the forces into x and y components
Resolving into x component :
Sum of forces = 3500 - 500 = 3000N
Resolving into y component:
Sum of forces = 2000N
Resultant force Fr = sqrt ( Fx^2 + Fy^2)
Fr = sqrt ( 3000^2 + 2000^2 )
Fr = sqrt ( 9000000 + 4000000 )
Fr = sqrt ( 13000000)
Fr = 3605.6 N
Therefore, resultant force acting on the wing is 3605.6 N
The direction of the vector will be:
Tan Ø = Fy / Fx
Substitute Fx and Fy into the formula
Tan Ø = 2000 / 3000
Tan Ø = 0.66666
Ø = tan^-1(0. 66666)
Ø = 33.7 degree.
