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Dimas [21]
4 years ago
12

Give a reason why, in a room at 30°c, T is stored in a sealed container.

Physics
2 answers:
puteri [66]4 years ago
7 0
Like that the heat of the room doesn't reach the what's inside the sealed container. Also for the sealed container to not let out the heat inside the container
Likurg_2 [28]4 years ago
4 0
The heat of the room Make it feel warm is Side the container
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Does a physical change affect the identity of a substance? Does a chemical change affect the identity of a substance?
eduard
Yes or no because I don't know and im tired
3 0
4 years ago
How does the shape of the moon change over 4 weeks
rodikova [14]

Answer: The Moon appears to change shape because we see different amounts of the lit part as the Moon orbits Earth. ... As it moves around Earth, more and more of the lit side comes into view. Then it begins to disappear again. It takes 29.5 days for the Moon to orbit Earth.

Explanation:look it up lol

4 0
3 years ago
What happens to the heat energy when you increase the length of an object​
Talja [164]

Answer: When the temperature of an object increases, the average kinetic energy of its particles increases. When the average kinetic energy of its particles increases, the object's thermal energy increases. Therefore, the thermal energy of an object increases as its temperature increases.

8 0
3 years ago
1. Consider three objects: Object A is a hoop of mass m and radius r; Object B is a sphere
Zarrin [17]

a) Object C (the disk) has the greatest rotational inertia (\frac{3}{2}mr^2)

b) Object B (the sphere) has the smallest rotational inertia (\frac{4}{5}mr^2)

Explanation:

The moments of inertia of the three objects are the following:

1) For a hoop of negligible thickness, it is

I=MR^2

where M is its mass and R its radius. For the hoop in this problem,

M = m

R = r

Therefore, its moment of inertia is

I=(m)(r)^2=mr^2

2) For a solid sphere, the moment of inertia is

I=\frac{2}{5}MR^2

where M is its mass and R its radius. For the sphere in this problem,

M = 2m

R = r

Therefore, its moment of inertia is

I=\frac{2}{5}(2m)(r)^2=\frac{4}{5}mr^2

3) For a disk of negligible thickness, the moment of inertia is

I=\frac{1}{2}MR^2

where M is its mass and R its radius. For the disk in this problem,

M = 3m

R = r

Therefore, its moment of inertia is

I=\frac{1}{2}(3m)(r)^2=\frac{3}{2}mr^2

So now we can answer the two questions:

a) Object C (the disk) has the greatest rotational inertia (\frac{3}{2}mr^2)

b) Object B (the sphere) has the smallest rotational inertia (\frac{4}{5}mr^2)

Learn more about inertia:

brainly.com/question/2286502

brainly.com/question/691705

#LearnwithBrainly

7 0
4 years ago
How much energy is needed to melt 150 g of ice at 0°C to water? (1)(Lf =3.34˟ 10⁵ J/Kg)
NARA [144]

Answer:

5.01×10⁴ J.

Explanation:

Applying,

q = Cm....................... Equation 1

Where q = amount of heat needed to melt the ice, m = mass of the ice, C = specific latent heat of ice.

From the question,

Given: m = 150 g = (150/1000) kg = 0.15 kg, C = 3.34×10⁵ J/kg

Substitute these values into equation 1

q = (0.15×3.34×10⁵)

q = 0.501×10⁵ J

q = 5.01×10⁴ J.

5 0
3 years ago
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