Question

5. A student travels 11 m north and then turns around to travel 25 m south. If the total time of travel is 12 sec., find a) The student's average speed. b.) The student's average​

Answer 1

Explanation:

Given that,

A student travels 11 m north and then turns around to travel 25 m south.

Total time, t = 12 s

The total distance or the total path covered by the student is equal to 11 m + 25 m = 36 m

Displacement of the student or the shortest path covered is d = 25-11 = 14 m

(a) The student's average speed = total distance/total time

$s=\dfrac{36\ m}{12\ s}\\\\s=3\ m/s$

(b) The student's average velocity = total displacement/total time

$v=\dfrac{14\ m}{12\ s}\\\\v=1.17\ m/s$