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12345 [234]
2 years ago
6

Why is the light bulb not a closed system?

Physics
1 answer:
Nana76 [90]2 years ago
4 0

Answer:An incandescent light bulb gives only energy of the system in the form of heat. ... The roof of a house is stable but it receives energy from the surroundings and transfers energy through it towards lower temperature side which includes no mass transfer. So, it is best considered as closed system.

Explanation:

You might be interested in
What is the average speed for the entire graph?
Maru [420]

Answer:

Explanation:

Divide the total distance traveled by the total time spent traveling. This will give you your average speed. . So if Ben traveled 150 miles in 3 hours, 120 miles in 2 hours, and 70 miles in 1 hour, his average speed was about 57 mph.

7 0
2 years ago
-Plz Help Meh-<br> Calculate the acceleration of a car if the force is 450N and the mass is 1300kg.
Allisa [31]

Answer:

Explanation:

F=Ma

450=1300×a

Ans=0.346m/s²

4 0
3 years ago
A cart is driven by a large propeller or fan, which can accelerate or decelerate the cart. The cart starts out at the position x
mash [69]

Answer:

The acceleration of the cart is 1.0 m\s^2 in the negative direction.

Explanation:

Using the equation of motion:

Vf^2 = Vi^2 + 2*a*x

2*a*x = Vf^2 - Vi^2

a = (Vf^2 - Vi^2)/ 2*x

Where Vf is the final velocity of the cart, Vi is the initial velocity of the cart, a the acceleration of the cart and x the displacement of the cart.

Let x = Xf -Xi

Where Xf is the final position of the cart and Xi the initial position of the cart.

x = 12.5 - 0

x = 12.5

The cart comes to a stop before changing direction

Vf = 0 m/s

a = (0^2 - 5^2)/ 2*12.5

a = - 1 m/s^2

The cart is decelerating

Therefore the acceleration of the cart is 1.0 m\s^2 in the negative direction.

5 0
3 years ago
A 1200N load is to be lifted with 200N effort using a first class lever. At what distance
kipiarov [429]

Explanation:

Hey there!!

Let's simply work with it.

Here,

load = 1200N

Effort = 200N

Load distance = 15cm

We have,

According to the principle of lever.

L×LD = E×ED.

1200×15 = 200× ED.

18000 = 200ED.

ed =  \frac{18000}{200}

Therefore, Effort Distance = 90cm.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
3 years ago
Suppose we wish to use a 6.0 m iron bar to lift a heavy object by using it as a lever. If we place the pivot point at a distance
Ber [7]

Answer:

The maximum load that this person is able to lift is 34.3 N

Explanation:

Applying the balancing torque, the expression is equal:

F₁L₁ = F₂L₂

mgL_{1} =F_{2} L_{2}

Where

g = 9.8 m/s² = gravity

L₁ = 0.8 m

F₂ = 527 N

L₂ = 6 - 0.8 = 5.2 m

Replacing and clearing the mass m:

m=\frac{F_{2}L_{2}  }{gL_{1} } =\frac{527*5.2}{9.8*0.8} =3.5kg

The maximum load that this person is able to lift is:

F = m * g = 3.5 * 9.8 = 34.3 N

8 0
3 years ago
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